Challenge

Project 1

PROJECT 1

Business model Customer to Customer (C2C) allows customers to do business with each other. This model is growing fast with e-commerce platforms where sellers may be required to pay some amount and buyer can buy it without paying anything. E-Commerce website brings the seller and buyer to the same platform. 

Analyzing the user's database will lead to understanding the business perspective. Behaviour of the users can be traced in terms of business with exploration of the user’s database. 

Dataset: One .csv file with name users_data with 98913 rows and 27 columns

# 1.Create new schema as ecommerce

CREATE SCHEMA ecommerce;

# 2.Import .csv file users_data into MySQL USING

# (right click on ecommerce schema -> Table Data import Wizard -> Give path of the file -> Next -> choose options : Create a new table , select delete if exist -> next -> next)

#using the schema

USE ecommerce;

# 3.Run SQL command to see the structure of table

DESC users_data;

# 4.Run SQL command to select first 100 rows of the database

SELECT 

    *

FROM

    users_data

LIMIT 100;

# 5.how many distinct values exist in table for field country and language

SELECT 

    COUNT(DISTINCT country) country,

    COUNT(DISTINCT language) language

FROM

    users_data;

# 6.Check whether male users are having maximum followers or female users.

SELECT 

    SUM(socialNbFollowers) Followers_count, gender

FROM

    users_data

GROUP BY gender;

# 7.Calculate the total users those

#a.Uses Profile Picture in their Profile

#b.Uses Application for Ecommerce platform

#c.Uses Android app

#d.Uses ios app

SELECT 

    'Profile_pictures', COUNT(hasProfilePicture) COUNT

FROM

    users_data

WHERE

    hasProfilePicture = 'TRUE' 

UNION SELECT 

    'Application_uses', COUNT(hasAnyApp)

FROM

    users_data

WHERE

    hasAnyApp = 'TRUE' 

UNION SELECT 

    'Android_users', COUNT(hasAndroidApp)

FROM

    users_data

WHERE

    hasAndroidApp = 'TRUE' 

UNION SELECT 

    'Ios_users', COUNT(hasIosApp)

FROM

    users_data

WHERE

    hasIosApp = 'TRUE';

# 8.Calculate the total number of buyers for each country and sort the result in descending order of total number of buyers. (Hint: consider only those users having at least 1 product bought.)

SELECT 

    COUNT(productsBought), country

FROM

    users_data

WHERE

    productsBought >= 1

GROUP BY country

ORDER BY COUNT(productsBought) desc;

# 9.Calculate the total number of sellers for each country and sort the result in ascending order of total number of sellers. (Hint: consider only those users having at least 1 product sold.)

SELECT 

    COUNT(productsSold) sellers,country

FROM

    users_data

WHERE

    productsSold > 0

GROUP BY country

ORDER BY COUNT(productsSold) ASC;

# 10.Display name of top 10 countries having maximum products pass rate.

SELECT 

    COUNT(productsPassRate) pass_rate, country

FROM

    users_data

GROUP BY country

ORDER BY COUNT(productsPassRate) DESC

LIMIT 10;

#11.Calculate the number of users on an ecommerce platform for different language choices.

SELECT 

    COUNT(language) number_of_users, language

FROM

    users_data

GROUP BY language;

#12.Check the choice of female users about putting the product in a wishlist or to like socially on an ecommerce platform. (Hint: use UNION to answer this question.)

SELECT

' whishlist_products',

COUNT(productsWished) choices

FROM

users_data

WHERE

productsWished > 0 AND gender = 'F'

UNION SELECT

'Socially', COUNT(socialProductsLiked) choices2

FROM

users_data

WHERE

socialProductsLiked > 0 AND gender = 'F';

#13.Check the choice of male users about being seller or buyer. (Hint: use UNION to solve this question.)

SELECT 

    'SELLER', COUNT(productsSold) CHOICE

FROM

    users_data

WHERE

    productsSold > 0 AND gender = 'M' 

UNION SELECT 

    'BUYER', COUNT(productsBought) CHOICE2

FROM

    users_data

WHERE

    productsBought > 0 AND gender = 'M';

# 14.Which country is having maximum number of buyers?

SELECT 

    COUNT(productsBought) buyer, country

FROM

    users_data

WHERE

    productsBought > 0

GROUP BY country

ORDER BY COUNT(productsBought) DESC

LIMIT 1;

#15.List the name of 10 countries having zero number of sellers.

SELECT 

    productsSold, country

FROM

    users_data

WHERE

    productsSold = 0

GROUP BY country

LIMIT 10;

# 16.Display record of top 110 users who have used ecommerce platform recently.

SELECT 

    *

FROM

    users_data

ORDER BY daysSinceLastLogin ASC

LIMIT 110;

#17.Calculate the number of female users those who have not logged in since last 100 days.

SELECT 

    COUNT(daysSinceLastLogin) Number_of_Female_employees_not_loged_in_last100_days

FROM

    users_data

WHERE

    daysSinceLastLogin >= 100

        AND gender = 'F';

#18.Display the number of female users of each country at ecommerce platform.

SELECT 

    COUNT(gender) female_count, country

FROM

    users_data

WHERE

    gender = 'F' AND hasAnyApp='TRUE'

GROUP BY country;

#19.Display the number of male users of each country at ecommerce platform.

SELECT 

    COUNT(gender) male_count, country

FROM

    users_data

WHERE

    gender = 'M' AND hasAnyApp='TRUE'

GROUP BY country;

#20.Calculate the average number of products sold and bought on ecommerce platform by male users for each country.

SELECT 

    AVG(productsSold) PRODUCT_SOLD,

    AVG(productsBought) PRODUCT_BOUGHT,

    country COUNTRY

FROM

    users_data

WHERE

    gender = 'M' AND hasAnyApp = 'TRUE'

GROUP BY country;

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