Challenge

Project 1

Part A:

The three-phase diode rectifier is supplying approximately 2.2 kW load with VLL=208V at 60 Hz, Ls=1 mH and Cd=1100 μF, where Cd is the DC side capacitor. Design the circuit in one of the simulation platforms (MATLAB or Ltspice/Simetrix) and obtain the circuit waveforms. Based on their simulation studies find out the following:

Diode Current = 40 amp

Diode Voltage

as per simulation result diode having current arround 40 amp and voltage arround 380 Volt

here we need to choose more than than simlation value so IDP30E65D1 of infineon model is suitable for this application all values having under the limit current rating 65amp and blocking voltage 650 Volt

Average dc voltage output, peak-to-peak ripple, the input current THD, DPF and PF and average dc current. Also give the selected devices with justification

the input current THD

DPF = cos(0.2);
DPF = 0.980066577841242
Is1 = 32.7;
Is =sqrt((46.25)^2+(17.82)^2+(11.46)^2);
Is = 50.871863539681730
Df = Is1/Is;
Df = 0.642791471055369
pf = Df*DPF
pf = 0.629978437302773

Average dc voltage output

peak-to-peak ripple of out put Voltage

379-372 =7 volt

average dc current 35 amp

Part B:

A three-phase thyristor converter is supplied by 480V (line-line), 60 Hz source. Its internal inductance Ls1=0.2 mH. The converter has a series inductance Ls2=2.0 mH. The load is represented as RLE load with Ld=5 mH, rd=0 and Ed=600V and the delay angle is α=20°. Using the simulation obtain vs, is and vd waveforms and calculate Is1, Is, DPF, PF and % THD. Also give the selected thyristor based on the simulated studies with proper justification.

firing Angle = 20

T1 = (30+alpha)*(0.0167/360)
T2 = (150+alpha)*(0.0167/360)
T3 = (270+alpha)*(0.0167/360)
T4 = (210+alpha)*(0.0167/360)
T5 = (330+alpha)*(0.0167/360)
T6 = (90+alpha)*(0.0167/360)
T1 = round(T1,4)= 0.002300000000000
T2 = round(T2,4)=0.007900000000000
T3 = round(T3,4)=0.013500000000000
T4 = round(T4,4)=0.010700000000000
T5 = round(T5,4)=0.016200000000000
T6 = round(T6,4)=0.005100000000000

Diode Voltage

Diode Current

Input Voltage and Input Current

Output Voltage and Current

THD = 294%

fandamental of input Rms current

Is1 = 0.0523

DPF = cos(59.7);
DPF = 0.999952570648168
Is1 = 0.0523;
Is = sqrt((0.07)^2+(0.01)^2+(0.07)^2+(0.01)^2);
Is = 0.100000000000000
Df = Is1/Is;
Df = 0.523000000000000
pf = Df*DPF;
pf = 0.522975194448992
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