Problem set 2 -week 3 challenge

Throttle acceleration=16.25ft/s^2 or 195 in/sec^2

g=32.20 ft/sec^2 or 386 in/sec^2

Load transfer=(total weight* throttle acceleration*cg height)*(wheelbase*g)

=(3750*195*17) *(98*386)=328 lbs

Axle weight after acceleration

Front axle weight=front axle weight - load transfer=1734.5

Rear axel weight=rear axel weight +load transfer=2015.5 lbs

Wheel rate calculation

Front wheel rate=spring rate*motion ratio^2=450*.76^2=259.92

Rear wheel rate=650*.72^2=336.96

Front end deflection=(10.22*.5)/259.92=.630 in

Rer end deflection=(10.22*.5)/336.96=.48 in

Pitch angle=tan^-1((.630+.48)/wb)180/pi = .5.01

Pitch gradient=pitch/throttle accn=9.94

Front anti lift angle=tan^-1((13.22-11.5)28.5)/ (180/pi)=3.453

Rear anti squat angle=tan^-1((16-11.5)46)/ (180/pi)=6.115

Front swing arm angle=tan^-1(cg height/wheelbase)*180/pi=rear swing arm angle=9.841

Front anti lift%=0%

Rear anti squat %=6.115/9.814=.6225

Front end deflection(with comp)=.630in

Rear end deflection(with comp)=.48*(100-.622)/100=.471

Pitch angle=tan^-1(.630+.47)/96*(180/pi)=5.

Pitch gradient=4.54/.5046=9.01

To eliminate pitch angle

Front end diff= rear end deff=.630

Rear end diff with comp=.48*(100-x)/100=-.630

x=231.25

Rear anti squat angle%=231.25=(rear anti squat angle/rear swing arm angle)

rear anti squat angle=2273

tan^-1((16-11.5)/X)*180/pi=2273.

x=-1.9

Rear ic horizontal distance==-1.9

Rear ic horizontal distance is not correct plese coment me the correct calculation

rear anti squat angle=2273

tan^-1((16-11.5)/X)*180/pi=2273.

x=-1.9

Rear ic horizontal distance==-1.9