Challenge

Problem Set-1b Week 11Challenge : Basic Handling parameters

Inputs

Front Axle Weight = 1900 lb

Rear Axle Weight = 1552 lb

Wheelbase = 100.6 in =

Load (lb)

Cornering Stiffness (lb/deg)

225

67

450

121

675

171

900

225

1125

227

1350

300

Solutions:

  1. Ackermann steer angles:

Delta = L/R*180/pi

i. R = 500 ft = 6000 in

Delta = 100.6/6000*180/pi

= 0.96 deg

ii. R = 200 ft = 2400 in

Delta = 100.6/2400*180/pi

= 2.40 deg

iii. R = 50 ft = 600 in

Delta = 100.6/600*180/pi

= 9.61 deg

  1. Understeer Gradient:

Weight on one wheel at front, Wf = Front Axle Weight / 2

= 950 lb

Weight on one wheel at rear, Wr = Rear Axle weight / 2

= 776 lb

Using interpolation method to find the cornering stiffness values from the table of values given.

Interpolation formula => y = y1+(x-x1)*((y2-y1)/(x2-x1))

At Front,

x = 950, x1 = 900, x2 = 1125, y1 = 225, y2 = 227

Cornering Stiffness, Cf = 225+(950-1125)*((227-225)/(1125-900)

= 225.44 lb/deg

At Rear,

x = 776, x1 = 675, x2 = 900, y1 = 171, y2 = 225

Cornering Stiffness, Cr = 171+(776-900)*((225-171)/(900-675)

= 195.24 lb/deg

Understeer gradient, K = Wf/Cf)-Wr/Cr

K = 0.24 deg/g

  1. Characteristic Speed:

V_char = sqrt((57.3*L*g)/K)

= sqrt((57.3*100.6*32.2)/(12*0.24))

= 254.24 mph

  1. Lateral acceleration gain:

V= 60 mph = 88 ft/s

lateral acceleration gain, Ay/ delta = (V^2/(57.3*L*g))/(1 +(K*V^2)/(57.3*L*g))

= (88^2/(57.3*(100.6/12)*32.2))/(1+(254.24*88^2)/(57.3*(100.6/12)*32.2))

= 0.48

  1. Yaw velocity gain:

V= 60 mph = 88 ft/s

Yaw velocity gain, r/delta = (V/L)/(1+(K*V^2)/(57.3*L*g))

= (88/100.6)/(1+(254.24*88^2)/(57.3*100.6*32.2))

= 9.37 (deg/s)/deg

  1. Slideslip angle:

V= 60 mph = 88 ft/s

R = 800 ft

Slideslip angle , beta = 57.3*c/R - (Wr*V^2)/(Cr*R*g)

Where, c = (Wf*L)/(W)

= (1900*100.6) / ((1900+1552)*12)

= 4.61 ft

Interpolation : x = 1552, x1 = 1125, x2 = 1350, y1 = 257, y2 = 300

Cornering Stiffness, C = 257 + (1552-1125)*(300-257)/(1350-1125)

= 338.6 lb/deg

beta = 57.3*c/R - (Wr*V^2)/(Cr*R*g)

= 57.3*4.61/800-(1552*88^2)/(338.6*800*32.2)

= -1.04 deg

  1. The understeer gradient was calculated from the study of a model with 2 DOF and we consider only cornering Stiffness, which is a tire level property. Whereas in the real scenario, other systems like suspension, steering, etc will contribute to the Understeer Gradient.
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