Optimization of section modulus of the front hood of a car.
Material of the hood:
Stainless steel AISI 302- cold-rolled, Y = 520 Mpa
Section Modulus:
- Section modulus is an important factor for beam and flexural member design.
- Higher the section modulus, higher will be the resistance to bending.
- It is easier to calculate stresses in beam and an exact measure of strength of steel.
- If two beams are made of same material and comparing the “section modulus” of two beams, the beam with bigger section modulus will be tougher and more capable to withstand larger loads.
It is termed as the ratio of second moment of area and distance from N.A (Neutral axis) to the extreme fiber. Also it is the measure of strength of given member. It is indicated by S.
We know that the bending equation is,
σ / y = M / I (1)
Where,
σ = Bending stress
y = Distance between the neutral axis (where the max stress could cause failure) and the section’s most extreme fiber.
M = Bending moment about the section’s neutral axis (mass moment of inertia)
I = Second moment of area (area moment of inertia)
From equation (1),
σ = (M . y) / I (2)
Section modulus is,
S = I / y (3)
From equation (2) & (3),
σ = M / S (4)
Thus from equation (4) it is shown that, higher the section modulus, higher will be the resistance to bending.
Calculation
Section modulus calculation for the initial hood design
Figure 1: cross-section of initial hood design
From the above analysis, following inertia are obtained
Imax = 7.185*108 mm4
Imin = 1.634*106 mm4
y = 833.242/2 mm
From equation (3),
Smax = Imax / y = 7.185*108 / 416.621 = 1724589.014 mm3
Smin = Imin / y = 1.634*106 / 416.621 = 3922.03 mm3
Section modulus calculation for the optimized hood design
Section modulus is represented as,
S = I / y
Where,
I is the area moment of inertia. When the area increases, the area moment of inertia also increases. If area moment of inertia increases then the section modulus also increases
From the equation (3), it is shown that the section modulus is increases by increase in the sectional area.
Here the cross-section area is increased by offsetting the outer panel by 3 mm. So the cross-section area gets increased
Figure 2: Cross-section of optimized hood design
From the above analysis, following inertia are obtained
Imax = 9.61*108 mm4
Imin = 2.41*106 mm4
y = 834.733/2 mm
From equation (3),
Smax = Imax / y = 9.61*108 / 417.3665 = 2302532.67 mm3
Smin = Imin / y = 2.41*106 / 417.3665 = 5774.3 mm3
Table 1: Comparing the Hood design before and after optimization
|
Initial Hood |
Optimized Hood |
|||||
|
Inertia (mm4) |
Y distance (mm) |
Section modulus (mm3) |
Inertia (mm4) |
Y distance (mm) |
Section modulus (mm3) |
|
|
Max |
7.185*108 |
416.621 |
1724589.014 |
9.61*108 |
417.3665 |
2302532.67 |
|
Min |
1.634*106 |
416.621 |
3922.03 |
2.41*106 |
417.3665 |
5774.3 |
From the above table, it has been seen that, when the cross-section area increases the section modulus along with that the bending resistance also increases.