Frequency Analysis of a rotating shaft

Aim:

    To create the model in Solidworks according to dimensions that you see fit. Model it in Solidworks according to the image shown below,

and Conduct a frequency analysis and apply a bearing fixture on the stepped face of the rod at the two ends and perform the analysis.

Solution:

Setting up dimensional data:

             I have set dimensions based on the above model and the d view of the model is shown bellow ,

based on the above design data i have conducted the analysis using the hint given in the challenge.

Steps involved in design and analysis of the shaft:

Step 1: Design the shaft based on the design defined above based on the model shon in the challenge set the front plane for sketching and first draw a circle of diameter 20mm and then extrude it upto 25mm, then choose the face of the circle and start sketch by creating a circle of about 35mm and extrude it upto 150mm and then create a sketch on other face by creating a circle of about 120mm and extrude it upto 10mm and then do the same thing for create other end of the shaft and make all of them dimensionally constrained and save it as steped shaft.

step2:Analysis:

   Then procede on to the simulation option and start a new study and select the frequency study and then followed the sequence as seq below.

seq 1:First apply the material property to the shaft the material applied is Alloy steel which is default material.

seq 2:Then give the bearing support constrain to the smaller diameter of the shaft at the two ends which is initially steped and there is no other load is applied.

seq 3:Then mesh the model at very fine condition and the image is shown bellow.

seq 4:Run the simulation for all the five five frequence method

seq 5:After completing the analysis save the plot and all the plots are in correct mannar so no change in the chart option and the amplitude graph are shown below one by one.

Frequency Amplitude 1:

here the maximum amplitude is 1.369

Frequency Amplitude 2:

here the maximum amplitude is 7.010e-001

Frequency Amplitude 3:

here the maximum amplitude is 7.010e-001, for both frequency 2 and 3 the displacement of the shaft is displaced at different direction but has saame frequency this was due to node under consideration here at frequency 2 the node considered at x direction and for frequency 3 it is considered at y-direction.

Frequency Amplitude 4:

here the maximum amplitude is 1.405

Frequency Amplitude 5:

here the maximum amplitude is 1.405 here also for 4 and 5th frequency are same because the node count for 4th one 1 and for the node count in 5th one is 2.

then the crtical frequency for all the five amplitude is shown in the table

Mode No.	Frequency(Rad/sec)	Frequency(Hertz)	Period(Seconds)
1	0.43801	0.069712	14.345
2	3132.6	498.57	0.0020057
3	3132.9	498.62	0.0020055
4	13181	2097.8	0.0004767
5	13185	2098.4	0.00047656

Result:

   Finally i have set the dimensions for the given model and set it and designed it in the solidworks and run a frequency analysis and obatined the above plots and obtained the critical frequency as shoen in the tabel.