Flow over a cylinder
INTRODUCTION TO COMPUTATIONAL FLUID DYNAMICS:
It is a branch of fluid mechanics that uses numerical analysis and algorithms to solve fluid flow situations. High-performing computers are used to conduct the calculations required to simulate the interaction of liquids and gases with surfaces defined by boundary conditions. It has fascinated researchers, as it is a fast, accurate, and reliable method of analyzing the variation of hydrodynamic properties of the flow over and within a body.
ABOUT REYNOLD'S NUMBER:
Reynolds number can reveal whether the flow is laminar or turbulent. It is defined as,
Re = ρVD/μ
Where
V - average velocity at the inlet of a diffuser,
D - Diameter of the inlet,
ρ - Density of the test fluid
μ - Viscosity of the test fluid.
AIM:
To perform the Flow simulation of flow through a cylinder using SolidWorks flow simulation.
OBJECTIVE:
- To analyze the fluid flow over a cylinder by calculating Reynold's number for baseline simulation
- To increase the calculated Reynolds number to a factor of 20%, 40%, & 100%.
- To perform the simulation for all values of Reynold's number and to create an animation file for velocity-pressure.
PROCEDURE:
3D MODEL:
Here to perform the flow simulation of flow through a pipe, a cylinder is been sketched and extruded in the front plane with the below parameters (MKS System):
Diameter of the cylinder = 0.04m
Length of the cylinder = 0.2m
BASELINE SIMULATION PARAMETERS:
To perform the flow simulation over the cylinder, let us assume the velocity of air to be 5m/s to calculate the Reynolds for the baseline simulation:
|
INPUT PARAMETERS |
VALUES |
|
Analysis Type |
External Flow |
|
Fluid |
Air |
|
Global Mesh Level |
5 |
|
Initial Velocity |
5 m/s |
|
Density |
1.125 kg/m^3 |
|
Diameter |
0.04 m |
|
Dynamic Viscosity |
18.14*10^-6 Ns/m^2 |
|
Time-dependent |
Total Analysis Time: 0.16 s Output time step: 0.016 s |
Re = ρVD/μ
Where
V - average velocity at the inlet of a diffuser,
D - Diameter of the inlet,
ρ - Density of the test fluid
μ - Viscosity of the test fluid.
By substituting the known values we get, the baseline Reynolds number is calculated as,
Re = 13,506.06
Similarly, Reynold's number at 20, 40 and 100 % is been calculated below,
Reynolds number by a factor of 20%:
To perform the flow simulation over the cylinder, let us take the Reynolds number factor as 20%:
Re = 13506.06 + (20% of 13506.06)
Re = 16,207.27
Reynolds number by a factor of 40%:
To perform the flow simulation over the cylinder, let us take Reynolds number factor as 100%:
Re = 16,207.27 + (40% of 16,207.27)
Re = 18,908.48
Reynolds number by a factor of 100%:
To perform the flow simulation over the cylinder, let us take Reynolds number factor as 100%:
Re = 27,012.12+ (40% of 27,012.12)
Re = 27,012.12
SIMULATION END TIME:
We know that Velocity = Distance/time, on rearranging we get end time for the baseline simulation as:
Since the length of the domain along the X-axis is 0.4 m. Then,
Time = Distance / velocity
= 0.4/5
= 0.08 s
Given that the end time should be 2 times the flow-through time. Then Simulation End Time = 0.16 s
|
|
Velocity |
Reynolds Number |
Simulation End Time (2 times the flow-through time) |
|
Baseline |
5 m/s |
13,506.06 |
0.16 |
|
At 20% |
6 m/s |
16,207.27 |
0.133 |
|
At 40% |
7 m/s |
18,908.48 |
0.114 |
|
At 100% |
10 m/s |
27,012.12 |
0.08 |
From the above study, the Velocity increases with a decrease in time.
RESULT:
1) Flow over a cylinder | Baseline Simulation:
Velocity = 5m/s
Re = 13,506.06
Simulation end time = 0.16 (2 times the flow-through time)
Velocity contour | cut plot:
Pressure contour | cut plot:
2) At 20% of Reynolds Number | Flow over a cylinder:
Velocity = 6m/s
Re = 16,207.27
Simulation end time = 0.133 (2 times the flow-through time)
Velocity contour | cut plot:
Pressure contour | cut plot:
3) At 40% of Reynolds Number | Flow over a cylinder:
Velocity = 7m/s
Re = 18,908.48
Simulation end time = 0.114 (2 times the flow-through time)
Velocity contour | cut plot:
Pressure contour | cut plot:
4) At 100% of Reynolds Number | Flow over a cylinder:
Velocity = 10m/s
Re = 27,012.12
Simulation end time = 0.08 (2 times the flow-through time)
Velocity contour | cut plot:
Pressure contour | cut plot:
CONCLUSION:
As a result, the above flow simulation study clearly shows that:
|
|
Velocity |
Reynolds Number |
Simulation End Time (2 times the flow-through time) |
|
Baseline |
5 m/s |
13,506.06 |
0.16 |
|
At 20% |
6 m/s |
16,207.27 |
0.133 |
|
At 40% |
7 m/s |
18,908.48 |
0.114 |
|
At 100% |
10 m/s |
27,012.12 |
0.08 |
- The Velocity increases with a decrease in time with respect to the Reynolds number
- When Reynold’s number increases, the flow over the cylinder becomes a steady flow.
- The velocity plot at 20% & 40% is slightly an unsteady flow plot whereas, at 100%, the flow is steady.
- In terms of Pressure, there is no significant change in the flow.
Thus the Flow simulation of flow through a cylinder is been simulated using the Solidworks flow simulation.