Challenge

Design of Shallow Foundation (Isolated Footings)

Gross soil pressure and footing area:

Unfactored load with surcharge + self weight of footing / allowable soil pressure

=(2000/1.5 x 1.1) /150 = 9.78 m2

Assuming we have sqaure footing √9.78=3.12 meter side footing consider, 3.2 meter sided isolate footing.

Net soil pressure and initial footing depth:

Factored Load/Actual Area footing= 2000 x 1000/ (3.2 x 3.2)

ρn = 195.3 Kn/m2

Assuming depth of footing 500mm and checking it for bearing stress as per IS-456-2000 clause 34.4-

√(footing base bearing area / loaded area)≤ 2

Permissible bearing stress 0.45 x fck=11.25 N/mm2

Permissible bearing stress multiply with area factor= 11.25 x 2 = 22.5N/mm2

Actual bearing stress at column = (2000 x 1000) / (400 x 400) = 12.5 N/mm2

12.5 N/mm2 actual stress is less than permissible 22.5N/mm2. Hence Okay.

We can proceed with 500mm depth footing for further design.

If we assume 50mm cover for footing the effective depth(d) shall be taken as 450mm

Flenural reinforcement=

Conversion of net pressure into Uniformly Distributed Load = 195.3 x 3.2 = 625 KN/m

Bending moment due to UDL over a cantilever section = WL2/2 = 625 x 1.6 x 1.6 /2 = 800 KN/m

Reinforcement calculation as per IS-456-2000 Annexure-G

μu= 0.87 fy Ast d (1-Ast.fy/bd.fck)

Assume fy=500 N/mm2

In result Ast required= 4350mm2

If we provide 16mm Dia rebar at 125mm spacing,the actual rebar provided= 3200/125 x 201

Ast provided= 5146 mm2

One way shear stress check:

Shear force in the one way area= 0.95 x 3.2 x 195.3 = 593.7 KN

Design shear stress at one way cut face τv =593.7 x 1000/ (3200 x 450) = 0.412 N/mm2

Shear stress capacity of section as per IS -456-2000 table-19 = 0.425N/mm2

Design shear stress is less than shear capacity-HENCE OKAY

Two way shear stress check:

Shear force in the two way shadded area = (3.2 x 3.2) - (0.85 x 0.85) x 195.3 = 1859 KN

Design shear stress at TWO WAY cut force τv = 1859 x 1000 / (3400 x 450) = 1.215N/mm2

Shear Stress capacity at section as per IS- 456-2000 clause 31.6.3.1

= 0.25 x √ Fck = 1.25 N/mm2

Design shear stress is less than shear capacity - HENCE OK

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