Basics of ML & AL Week 2 Challenge
1)Calculate all 4 business moments using pen and paper for the below data set?
| x | p(x) | p*p(x) | X-mean | (X-mean)2*x | ((X-mean)/variance))^3 | ((X-mean)/variance))^4 |
| 0 | 0.35 | 0 | -1.4 | 0 | -0.012918411373136 | 0.003031182931448 |
| 1 | 0.25 | 0.25 | -0.4 | 0.16 | -0.00030130405535 | 2.01994697639187E-05 |
| 2 | 0.15 | 0.3 | 0.6 | 0.72 | 0.001016901186807 | 0.00010225981568 |
| 3 | 0.15 | 0.45 | 1.6 | 7.68 | 0.019283459542407 |
0.005171064259563 |
| 4 | 0.1 | 0.4 | 2.6 | 27.04 | 0.082745626200524 | 0.036057315995455 |
mean 1.4 standard deviation 35.6 0.089826271501251 0.04438202247191
variance 5.96657355607052
Skewness 0.089826271501251
kurtosis 0.04438202247191
2.What is the significance of expected value when simple mean (Sum of all observations/number of observations) is already
in place?
-> Expected mean is weighted mean for random variables in a probability distribution.Simple mean is average for a given sample.
3.Having skewness in the curve considered to be bad in the analysis?
-> Having a skewness is disoration of the curve from the normal distribution.It is not either good or bad to have a skewness in the curve.
4.Evaluate the probabilities for continuous normal distribution with given mean = 680 and standard deviation = 31 z =(x-mean)/standard deviation.
a.P(X<711)
z = 1
84.12%
b.P(X>740)
z = 1.9 = 2
2.27%
c.P(600<x<720)
83.99%
d.P(X=720)
0%
5)Explain the curve on the right side.
-> The right side of the normal distribution represents the high chance of finding better performer or best scoring student or higher paid employees.