Challenge

Basics of ML & AL Week 2 Challenge

1. a) mean= ∑ (xi)P(x) = 1.4

b) variance= ∑( (xi)-u(i) )^2= 1.84

c)skewness=∑( ((xi)-u(i) )/σ)^3 * P(x) =0.571

d)kurtosis=∑( ((xi)-u(i) )/σ)^4* P(x)-3 =2.083

3) having skewness is data can be either bad or good it depends on type of analysis we are going to perform.

2) Average is a special scenario of expected value in which all the probabilities are equal. so when there is uniform probability distribution for all random variables we can directly use mean or otherwise we have to take the weighted average of all.

4) a) 0.9983

b)0.0265

c)0.8966

d)not defined

5) right side represent all probabilities of x>680

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