Challenge

Analysis & Design of RCC shear walls in the model using ETABS

Ans:

Aim:-To provide the exact values of longitudinal steel ratio, boundary element length and shear reinforcing ratio from the design results.

To provide c/s steel arrangements of shear wall from its base upto terrace ,as per IS 13290-2016

To provide elevation drawings of the reinforcement details of the shear wall from base upto terrace.

Procedure: -

1.Shear walls are vertical elements of the horizontal force resisting system

  1. They are constructed to counter the effect of lateral load acting on a structure.

3.When the shear walls are designed and constructed properly, they will have strength and stiffness to resist the horizontal forces.

4.Shear walls are highly imported in the high rise buildings which are subjected to wind and seismic forces.

Steps;-

  1. In the first step open the given Etabs file and click on the run the analysis option.
  2. Once the analysis is done completely.
  3. In the next step go to shear wall design and select start design/check the structure.
  4. In the next step go to shear wall design and select display design info.
  5. Select the p-m failure.
  6. We can observe that there are no failures in the A-11 grid shear wall.
  7. Select the shear failure.
  8. We can observe that there are no failures in the A-11 grid shear wall.
  9. In the next step click display design info and select the longitudinal pier reinforcing.

Longitudinal pier Reinforcing of the Grid A 11

Sl.no

Storeys

Top

Bottom

1

Base

6998

13128

2

Ground

3072

8273

3

First

2154

4896

4

second

2249

2577

5

Thired

2154

1725

6

Fourth

2122

1125

7

Fifth

2150

1125

  1. In the next step click on the longitudinal pier steel ration the value for the A11 grid is as follow

Longitudinal pier Reinforcing Steel Ratip of the Grid A 11

Sl.no

Storeys

Top

Bottom

1

Base

0.0156

0.0292

2

Ground

0.0068

0.0184

3

First

0.0048

0.0109

4

second

0.005

0.0057

5

Thired

0.0048

0.0038

6

Fourth

0.0047

0.0025

7

Fifth

0.0048

0.0025

  1. As per clause number 1.1. of Is 13290 2016 the minimum thickness of the wall should not be less than 150 mm or 300 mm in case of shear walls. So in the question its being given that the thickness of shear wall is 300 mm hence it is safe.
  2. As per clause number 1.2. of Is 13290 2016 the minimum ratio of length of the wall to its shall be equal to 4.

=1500/300

=5 >4 hence ok.

  1. As per clause number 1.3. of Is 13290 2016

Height of the wall=21m, length of the wall=1.5 m

hw/lw=21/1.5=14 hence the wall is slender wall.

Longitudinal pier Reinforcing Steel Ratip of the Grid A 11

Sl.no

Storeys

Top

Bottom

1

Base

0.0156

0.0292

2

Ground

0.0068

0.0184

3

First

0.0048

0.0109

4

second

0.005

0.0057

5

Thired

0.0048

0.0038

6

Fourth

0.0047

0.0025

7

Fifth

0.0048

0.0025

All these above values are less than 4%. Hence the shear wall is safe.

  1. In the next step go to shear wall design icon and click on display design info and select boundary element.

Boundry elements length of the Grid A 11

EDGE length in mm

Sl.No

Top-Left

Top -Right

Bottom-left

Bottom-Right

1

Foundation to base

450

300

600

450

2

Base to GF

300

300

450

300

3

GF to 1st Floor

0

0

300

300

4

1st to 2nd

0

300

300

300

5

2nd to 3rd

0

300

300

0

6

3rd to 4th

0

300

0

0

7

4th to 5th

0

300

0

0

  1. Minimum Reinforcement in shear walls calculation as per Table 1. Of IS 13290-2016.

iii.Slender walls

Lw=1500 mm,tw=300 mm hw=21000 mm

(ρh )min=0.0025+0.5((hw/Lw)-2)( ρh -0.0025)

=0.0025+0.5((21000/1500)-2)(0.0292-0.0025)

=0.1627

(ρv,be)min=0.0080

(ρv,wee)min=0.0025

((ρv,net)min=0.0025+0.01375(tw/Lw)

=0.0025+0.01375(300/1500)

=5.25*10^-3

  1. As per the 10.1.7 of Is 13290-2016 ,Rinforcement bars shall be provided two curtains within the c/s of the wall ,with each curtain having bars running along vertical and horizontal directions when.
  2. Factored shear stress demand in the wall exceeds 0.25sqrt fck
  3. Or Wall thick ness is 200 mm or higher

In our case the all the stress are above 5. And wall thickness provided is 300 mm .

Boundry elements length of the Grid A 11

EDGE length in mm

Sl.No

Top-Left

Top -Right

Bottom-left

Bottom-Right

1

Foundation to base

450

300

600

450

2

Base to GF

300

300

450

300

3

GF to 1st Floor

0

0

300

300

4

1st to 2nd

0

300

300

300

5

2nd to 3rd

0

300

300

0

6

3rd to 4th

0

300

0

0

7

4th to 5th

0

300

0

0

  1. As per 10.4.1. of IS 13290-2016 Boundry elements will be provided along the vertical boundaries of walls ,when the extreme fibre compressive stress in the walls exceeds.

In Grid A11 the shear wall at the base level if we check all the values of compressive stress are exceeding 0.2fck=0.2*25=5N/mm^2.

  1. So since we require boundry elements in the Shear wall at the base

The special confining reinforcement as per 10.4.4.4 of IS 13290-2016 is

Ash=0.05 Sv h fck/fy

There fore using 8mm dia bars

Ash=22/7*8*8*0.25

=50.26 mm^2

fck=25,fy=500

Ash=0.05 Sv h fck/fy

50.26=0.05*100*h*25/500

Sv=201.0mm

Longitudinal pier Reinforcing of the Grid A 11
1 Base to Ground floor level
Height of the shear wall 21000 mm
Thickness of the wall 300 mm
length of the wall 1500 mm
fck Mpa 25 Mpa
fy 500 Mpa
Sv 100 mm
Boundry elements length from Etabs
Top-Left Top -Right Bottom-left Bottom-Right
450 300 600 450
Boundry element length to be provided on either end is 600 mm
So the web length will be left with 300 mm
which is nothing there fore on the entire length the reinforcement of boundry element is provided.
Type of wall As per 10.1.4 of IS 13290-2016
hw/lw 14
Slender wall
Boundary element Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment in BE is (ρ v min) for 0.0008
Minimum Area of Reinforcement 360 mm^2
Longitudinal Reinforcment required
Area of Rebar required from the etabs Av 13128 (mm^2)
Dia of bars used in mm 25
Area of one rebar Av 490.9375 (mm^2)
Number of bars required No.s 26.74067473
Spacing of the bars
Ash=0.05 Sv h fck/fy
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
h=Ash*fy/0.05 Sv fck mm 201.088
As per 10.1.8 of Is 13290 2016 the largest dia used in longitudinbal bars 1/10th of thickness of that
a) Thickness used mm 300
1/10th of thickness mm 30
dia of bars used mm 13128
FALSE
As per 10.1.9 of Is 13290 2016maximum spacing of vertical/horizontal reinforcement should be smaller of
a)1/5th of horizontal length mm 300
b)3 times the thickness tw of web mm 900
c) 450 mm mm 450
provided spacing mm 200
hence 26 numbers 25 mm dia bars are provided at 120mm c/c
Shear Reinforcment required
Ash from Etabs mm^2 750
As per 10.4.4 of IS 13290-2016
The spacing between the reinforcement in the special confining zone shall not be lesser of
a)1/3rd of minimum dimension of BE 0 mm
b)6times the longitudinal dia bars 0 mm
c)100 mm 100 mm
Values from etabs
Minimum Spacing 0 mm
100 mm
There fore spacing provided in the confining zone of Boundry element in mm
Ashear reinforcement from Etabs mm^2 750
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
Number of bars 7.459420751
Nos. 8
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 100 mm c/c in entire region.
2 GF level to 1st floor
Height of the shear wall 21000 mm
Thickness of the wall 300 mm
length of the wall 1500 mm
fck Mpa 25 Mpa
fy 500 Mpa
Sv 100 mm
Boundry elements length from Etabs
Top-Left Top -Right Bottom-left Bottom-Right
300 300 450 300
Boundry element length to be provided on either end is 450 mm
So the web length will be left with 600 mm
which is nothing there fore on the entire length the reinforcement of boundry element is provided.
Type of wall As per 10.1.4 of IS 13290-2016
hw/lw 14
Slender wall
Boundary element Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment in BE is (ρ v min) for 0.0008
Minimum Area of Reinforcement 360 mm^2
Longitudinal Reinforcment required
Area of Rebar required from the etabs Av 8273 (mm^2)
Dia of bars used in mm 25
Area of one rebar Av 490.9375 (mm^2)
Number of bars required No.s 16.85143221
Spacing of the bars
Ash=0.05 Sv h fck/fy
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
h=Ash*fy/0.05 Sv fck mm 201.088
As per 10.1.8 of Is 13290 2016 the largest dia used in longitudinbal bars 1/10th of thickness of that
a) Thickness used mm 300
1/10th of thickness mm 30
dia of bars used mm 25
Clause 10.1.8 is satisfied
As per 10.1.9 of Is 13290 2016maximum spacing of vertical/horizontal reinforcement should be smaller of
a)1/5th of horizontal length mm 300
b)3 times the thickness tw of web mm 900
c) 450 mm mm 450
provided spacing mm 200
hence 16 numbers 25 mm dia bars are provided at 120mm c/c
Shear Reinforcment required
Ash from Etabs mm^2 750
As per 10.4.4 of IS 13290-2016
The spacing between the reinforcement in the special confining zone shall not be lesser of
a)1/3rd of minimum dimension of BE 99 mm
b)6times the longitudinal dia bars 150 mm
c)100 mm 100 mm
Values from etabs
Minimum Spacing 99 mm
100 mm
There fore spacing provided in the confining zone of Boundry element in mm
Ashear reinforcement from Etabs mm^2 750
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
Number of bars 7.459420751
Nos. 8
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 100 mm c/c in entire region.
3 First Floor level to 2nd Floor
Height of the shear wall 21000 mm
Thickness of the wall 300 mm
length of the wall 1500 mm
fck Mpa 25 Mpa
fy 500 Mpa
Sv 100 mm
Boundry elements length from Etabs
Top-Left Top -Right Bottom-left Bottom-Right
0 0 300 0
Boundry element length to be provided on either end is 300 mm
So the web length will be left with 900 mm
in this case both boundery elements and web is provided.
Type of wall As per 10.1.4 of IS 13290-2016
hw/lw 14
Slender wall
Boundary element Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment in BE is (ρ v min) for 0.0008
Minimum Area of Reinforcement 360 mm^2
Longitudinal Reinforcment required
Area of Rebar required from the etabs Av 4896 (mm^2)
Dia of bars used in mm 25
Area of one rebar Av 490.9375 (mm^2)
Number of bars required No.s 9.972756206
Spacing of the bars
Ash=0.05 Sv h fck/fy
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
h=Ash*fy/0.05 Sv fck mm 201.088
As per 10.1.8 of Is 13290 2016 the largest dia used in longitudinbal bars 1/10th of thickness of that
a) Thickness used mm 300
1/10th of thickness mm 30
dia of bars used mm 25
Clause 10.1.8 is satisfied
As per 10.1.9 of Is 13290 2016maximum spacing of vertical/horizontal reinforcement should be smaller of
a)1/5th of horizontal length mm 300
b)3 times the thickness tw of web mm 900
c) 450 mm mm 450
provided spacing mm 200
hence 10 numbers 25 mm dia bars are provided at 200mm c/c
Shear Reinforcment required
Ash from Etabs mm^2 750
As per 10.4.4 of IS 13290-2016
The spacing between the reinforcement in the special confining zone shall not be lesser of
a)1/3rd of minimum dimension of BE 0 mm
b)6times the longitudinal dia bars 2945.625 mm
c)100 mm 100 mm
Values from etabs
Minimum Spacing 0 mm
100 mm
There fore spacing provided in the confining zone of Boundry element in mm
Ashear reinforcement from Etabs mm^2 750
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
Number of bars 7.459420751
Nos. 8
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 100 mm c/c in Boundry element.
web region Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment inweb is (ρ v min) for 0.0025
vertical reinforcemment inweb is (ρ vnet) for 0.00525
Area of vertical reinforcement required 23.625 mm^2
Using 8 mm 2 legged dia bars
dia of bar mm 8
legged 2
Area of one bar mm^2 100.544
Spacing mm 125
Number of bars
Area of shear reinforcment provided mm^2 804.352
required mm^2 750
Hence ok
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 120 mm c/c in Boundry element region.
3 FF to SF
Height of the shear wall 21000 mm
Thickness of the wall 300 mm
length of the wall 1500 mm
fck Mpa 25 Mpa
fy 500 Mpa
Sv 100 mm
Boundry elements length from Etabs
Top-Left Top -Right Bottom-left Bottom-Right
0 300 300 300
Boundry element length to be provided on either end is 300 mm
So the web length will be left with 900 mm
in this case both boundery elements and web is provided.
Type of wall As per 10.1.4 of IS 13290-2016
hw/lw 14
Slender wall
Boundary element Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment in BE is (ρ v min) for 0.0008
Minimum Area of Reinforcement 360 mm^2
Longitudinal Reinforcment required
Area of Rebar required from the etabs Av 4896 (mm^2)
Dia of bars used in mm 25
Area of one rebar Av 490.9375 (mm^2)
Number of bars required No.s 9.972756206
Spacing of the bars
Ash=0.05 Sv h fck/fy
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
h=Ash*fy/0.05 Sv fck mm 201.088
As per 10.1.8 of Is 13290 2016 the largest dia used in longitudinbal bars 1/10th of thickness of that
a) Thickness used mm 300
1/10th of thickness mm 30
dia of bars used mm 25
Clause 10.1.8 is satisfied
As per 10.1.9 of Is 13290 2016maximum spacing of vertical/horizontal reinforcement should be smaller of
a)1/5th of horizontal length mm 300
b)3 times the thickness tw of web mm 900
c) 450 mm mm 450
provided spacing mm 200
hence 10 numbers 25 mm dia bars are provided at 200mm c/c
Shear Reinforcment required
Ash from Etabs mm^2 750
As per 10.4.4 of IS 13290-2016
The spacing between the reinforcement in the special confining zone shall not be lesser of
a)1/3rd of minimum dimension of BE 0 mm
b)6times the longitudinal dia bars 2945.625 mm
c)100 mm 100 mm
Values from etabs
Minimum Spacing 0 mm
100 mm
There fore spacing provided in the confining zone of Boundry element in mm
Ashear reinforcement from Etabs mm^2 750
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
Number of bars 7.459420751
Nos. 8
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 100 mm c/c in Boundry element.
web region Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment inweb is (ρ v min) for 0.0025
vertical reinforcemment inweb is (ρ vnet) for 0.00525
Area of vertical reinforcement required 23.625 mm^2
Using 8 mm 2 legged dia bars
dia of bar mm 8
legged 2
Area of one bar mm^2 100.544
Spacing mm 125
Number of bars
Area of shear reinforcment provided mm^2 804.352
required mm^2 750
Hence ok
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 120 mm c/c in Boundry element region.
4 2ND TO 3RD FLOOR
Height of the shear wall 21000 mm
Thickness of the wall 300 mm
length of the wall 1500 mm
fck Mpa 25 Mpa
fy 500 Mpa
Sv 100 mm
Boundry elements length from Etabs
Top-Left Top -Right Bottom-left Bottom-Right
0 300 300 300
Boundry element length to be provided on either end is 300 mm
So the web length will be left with 900 mm
in this case both boundery elements and web is provided.
Type of wall As per 10.1.4 of IS 13290-2016
hw/lw 14
Slender wall
Boundary element Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment in BE is (ρ v min) for 0.0008
Minimum Area of Reinforcement 360 mm^2
Longitudinal Reinforcment required
Area of Rebar required from the etabs Av 2577 (mm^2)
Dia of bars used in mm 20
Area of one rebar Av 314.2 (mm^2)
Number of bars required No.s 8.201782304
Spacing of the bars
Ash=0.05 Sv h fck/fy
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
h=Ash*fy/0.05 Sv fck mm 201.088
As per 10.1.8 of Is 13290 2016 the largest dia used in longitudinbal bars 1/10th of thickness of that
a) Thickness used mm 300
1/10th of thickness mm 30
dia of bars used mm 25
Clause 10.1.8 is satisfied
As per 10.1.9 of Is 13290 2016maximum spacing of vertical/horizontal reinforcement should be smaller of
a)1/5th of horizontal length mm 300
b)3 times the thickness tw of web mm 900
c) 450 mm mm 450
provided spacing mm 200
hence 8 numbers 20 mm dia bars are provided at 200mm c/c
Shear Reinforcment required
Ash from Etabs mm^2 750
As per 10.4.4 of IS 13290-2016
The spacing between the reinforcement in the special confining zone shall not be lesser of
a)1/3rd of minimum dimension of BE 0 mm
b)6times the longitudinal dia bars 1885.2 mm
c)100 mm 100 mm
Values from etabs
Minimum Spacing 0 mm
100 mm
There fore spacing provided in the confining zone of Boundry element in mm
Ashear reinforcement from Etabs mm^2 750
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
Number of bars 7.459420751
Nos. 8
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 100 mm c/c in Boundry element.
web region Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment inweb is (ρ v min) for 0.0025
vertical reinforcemment inweb is (ρ vnet) for 0.00525
Area of vertical reinforcement required 23.625 mm^2
Using 8 mm 2 legged dia bars
dia of bar mm 8
legged 2
Area of one bar mm^2 100.544
Spacing mm 125
Number of bars
Area of shear reinforcment provided mm^2 804.352
required mm^2 750
Hence ok
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 120 mm c/c in Boundry element region.
5 3RD TO 4TH FLOOR
Height of the shear wall 21000 mm
Thickness of the wall 300 mm
length of the wall 1500 mm
fck Mpa 25 Mpa
fy 500 Mpa
Sv 100 mm
Boundry elements length from Etabs
Top-Left Top -Right Bottom-left Bottom-Right
0 300 300 0
Boundry element length to be provided on either end is 300 mm
So the web length will be left with 900 mm
in this case both boundery elements and web is provided.
Type of wall As per 10.1.4 of IS 13290-2016
hw/lw 14
Slender wall
Boundary element Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment in BE is (ρ v min) for 0.0008
Minimum Area of Reinforcement 360 mm^2
Longitudinal Reinforcment required
Area of Rebar required from the etabs Av 2154 (mm^2)
Dia of bars used in mm 20
Area of one rebar Av 314.2 (mm^2)
Number of bars required No.s 6.855506047
Spacing of the bars
Ash=0.05 Sv h fck/fy
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
h=Ash*fy/0.05 Sv fck mm 201.088
As per 10.1.8 of Is 13290 2016 the largest dia used in longitudinbal bars 1/10th of thickness of that
a) Thickness used mm 300
1/10th of thickness mm 30
dia of bars used mm 25
Clause 10.1.8 is satisfied
As per 10.1.9 of Is 13290 2016maximum spacing of vertical/horizontal reinforcement should be smaller of
a)1/5th of horizontal length mm 300
b)3 times the thickness tw of web mm 900
c) 450 mm mm 450
provided spacing mm 200
hence7 numbers 20 mm dia bars are provided at 200mm c/c
Shear Reinforcment required
Ash from Etabs mm^2 750
As per 10.4.4 of IS 13290-2016
The spacing between the reinforcement in the special confining zone shall not be lesser of
a)1/3rd of minimum dimension of BE 0 mm
b)6times the longitudinal dia bars 1885.2 mm
c)100 mm 100 mm
Values from etabs
Minimum Spacing 0 mm
100 mm
There fore spacing provided in the confining zone of Boundry element in mm
Ashear reinforcement from Etabs mm^2 750
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
Number of bars 7.459420751
Nos. 8
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 100 mm c/c in Boundry element.
web region Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment inweb is (ρ v min) for 0.0025
vertical reinforcemment inweb is (ρ vnet) for 0.00525
Area of vertical reinforcement required 23.625 mm^2
Using 8 mm 2 legged dia bars
dia of bar mm 8
legged 2
Area of one bar mm^2 100.544
Spacing mm 125
Number of bars
Area of shear reinforcment provided mm^2 804.352
required mm^2 750
Hence ok
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 120 mm c/c in Boundry element region.
6 4TH TO 5TH FLOOR
Height of the shear wall 21000 mm
Thickness of the wall 300 mm
length of the wall 1500 mm
fck Mpa 25 Mpa
fy 500 Mpa
Sv 100 mm
Boundry elements length from Etabs
Top-Left Top -Right Bottom-left Bottom-Right
0 300 0 0
Boundry element length to be provided on either end is 300 mm
So the web length will be left with 900 mm
in this case both boundery elements and web is provided.
Type of wall As per 10.1.4 of IS 13290-2016
hw/lw 14
Slender wall
Boundary element Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment in BE is (ρ v min) for 0.0008
Minimum Area of Reinforcement 360 mm^2
Longitudinal Reinforcment required
Area of Rebar required from the etabs Av 2122 (mm^2)
Dia of bars used in mm 20
Area of one rebar Av 314.2 (mm^2)
Number of bars required No.s 6.753660089
Spacing of the bars
Ash=0.05 Sv h fck/fy
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
h=Ash*fy/0.05 Sv fck mm 201.088
As per 10.1.8 of Is 13290 2016 the largest dia used in longitudinbal bars 1/10th of thickness of that
a) Thickness used mm 300
1/10th of thickness mm 30
dia of bars used mm 25
Clause 10.1.8 is satisfied
As per 10.1.9 of Is 13290 2016maximum spacing of vertical/horizontal reinforcement should be smaller of
a)1/5th of horizontal length mm 300
b)3 times the thickness tw of web mm 900
c) 450 mm mm 450
provided spacing mm 200
hence7 numbers 20 mm dia bars are provided at 200mm c/c
Shear Reinforcment required
Ash from Etabs mm^2 750
As per 10.4.4 of IS 13290-2016
The spacing between the reinforcement in the special confining zone shall not be lesser of
a)1/3rd of minimum dimension of BE 0 mm
b)6times the longitudinal dia bars 1885.2 mm
c)100 mm 100 mm
Values from etabs
Minimum Spacing 0 mm
100 mm
There fore spacing provided in the confining zone of Boundry element in mm
Ashear reinforcement from Etabs mm^2 750
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
Number of bars 7.459420751
Nos. 8
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 100 mm c/c in Boundry element.
web region Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment inweb is (ρ v min) for 0.0025
vertical reinforcemment inweb is (ρ vnet) for 0.00525
Area of vertical reinforcement required 23.625 mm^2
Using 8 mm 2 legged dia bars
dia of bar mm 8
legged 2
Area of one bar mm^2 100.544
Spacing mm 125
Number of bars
Area of shear reinforcment provided mm^2 804.352
required mm^2 750
Hence ok
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 120 mm c/c in Boundry element region.
6 5TH TO Terrace
Height of the shear wall 21000 mm
Thickness of the wall 300 mm
length of the wall 1500 mm
fck Mpa 25 Mpa
fy 500 Mpa
Sv 100 mm
Boundry elements length from Etabs
Top-Left Top -Right Bottom-left Bottom-Right
0 300 0 0
Boundry element length to be provided on either end is 300 mm
So the web length will be left with 900 mm
in this case both boundery elements and web is provided.
Type of wall As per 10.1.4 of IS 13290-2016
hw/lw 14
Slender wall
Boundary element Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment in BE is (ρ v min) for 0.0008
Minimum Area of Reinforcement 360 mm^2
Longitudinal Reinforcment required
Area of Rebar required from the etabs Av 2150 (mm^2)
Dia of bars used in mm 20
Area of one rebar Av 314.2 (mm^2)
Number of bars required No.s 6.842775302
Spacing of the bars
Ash=0.05 Sv h fck/fy
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
h=Ash*fy/0.05 Sv fck mm 201.088
As per 10.1.8 of Is 13290 2016 the largest dia used in longitudinbal bars 1/10th of thickness of that
a) Thickness used mm 300
1/10th of thickness mm 30
dia of bars used mm 25
Clause 10.1.8 is satisfied
As per 10.1.9 of Is 13290 2016maximum spacing of vertical/horizontal reinforcement should be smaller of
a)1/5th of horizontal length mm 300
b)3 times the thickness tw of web mm 900
c) 450 mm mm 450
provided spacing mm 200
hence7 numbers 20 mm dia bars are provided at 200mm c/c
Shear Reinforcment required
Ash from Etabs mm^2 750
As per 10.4.4 of IS 13290-2016
The spacing between the reinforcement in the special confining zone shall not be lesser of
a)1/3rd of minimum dimension of BE 0 mm
b)6times the longitudinal dia bars 1885.2 mm
c)100 mm 100 mm
Values from etabs
Minimum Spacing 0 mm
100 mm
There fore spacing provided in the confining zone of Boundry element in mm
Ashear reinforcement from Etabs mm^2 750
Dia of Shear reinforcemebt bars mm 8
Area of one rebar Av(mm^2) 50.272
Number of bars 7.459420751
Nos. 8
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 100 mm c/c in Boundry element.
web region Calculation
Asper Table 1 of IS 13290-2016
vertical reinforcemment inweb is (ρ v min) for 0.0025
vertical reinforcemment inweb is (ρ vnet) for 0.00525
Area of vertical reinforcement required 23.625 mm^2
Using 8 mm 2 legged dia bars
dia of bar mm 8
legged 2
Area of one bar mm^2 100.544
Spacing mm 125
Number of bars
Area of shear reinforcment provided mm^2 804.352
required mm^2 750
Hence ok
There fore 8 mm dia 2 legged shear reinforcemeint is provided at 120 mm c/c in Boundry element region.

Elevation of Shear wall Detailing.

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