Vehicle Dynamics -challenge 2 wk-1

https://drive.google.com/open?id=1YIl1F6sCkqUNOQ7yhnBIpVuAtvSboxiq

Answers-

1........................................................

Caster angle- 5.3145 (deg)

KPI- 10.0543(deg)

Scrub radius- 8.1258 mm

Mech_trail- 9.3023 mm

KPI_lateral offset ~ 85mm

KPI_longi_offset =18.6047mm

2........................................................

Restoring moment =

Lateral force*[(Pneumatic tail+Caster trail)/2]

2000*[(25+9.3023)/2]

=34302.4 N-mm

3.......................................................

For changing scrub radius sign we can shift LBJ by 25mm more towards (-Y axis)

% 1....Caster angle calculation-
%tan(z)=[{dist_between UBJ & LBJ/dist_between UBJ & wheel_center_axis}]
%y=dist_between UBJ & LBJ =430 
%x=dist_between UBJ & wheel_center_axis =40
% let z be the caster angle
x=40; y=430;
z=atand(x/y);

%2....Mechanical Trail calculation(OP)

% We have got caster angle so we use it to get mechnical trail
%tan(theta)=[{mech_trail/dist_between LBJ & pt of contact of wheel}]
% mech_trail =tand(z)*dist_between LBJ & pt of contact of wheel
OP=tand(z)*100;

%3....Kinpin inclination(Phi)
% complete the triangle in front view
% tand(Phi)=(FL/QL);
%See the graph for FL & QL)
FL=125; QL=705;
Phi=atand(FL/QL);

%4....Kingpin longitudinal offest(AM)
%Let M be the pt on wheel center line(x-axis)
%AM= (atand(z)*dist_between wheel center & LBJ)
AM=tand(z)*200;


%5....scrub radius(WN)
%Kingpin inclination angle(phi)
%Consider triangle WQN
WQ=180;
WN=atand(Phi)*WQ;