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SIDE POLE IMPACT TEST ASSIGNMENT 7

KKannan Saravanan5 May 2020
  • CASE SETUP
      • Check unit system and either follow [Mg mm s] or [Kg mm ms].
      • Create appropriate interface ,friction 0.2 and recommended parameters.
      • Make sure of no penetration and intersections.
      • Create rigid wall with friction 0.1 as per referance model.
      • Compare the model weight with the referance model and use added masses to reach target weight 700kg while getting CG about the required range.
      • Initial velocity as shown in picture.
      • Use model checker to ensure good quality.
      • Timestep :0.5 to 0.1 microseconds.
      • Run 80ms.
  • Check unit system and either follow [Mg mm s] or [Kg mm ms].
      • AS PER INDUSTRY STANDARD WE FOLLOWING THE KG MM MS IN OUR ASSIGNMENT
  • Create appropriate interface ,friction 0.2 and recommended parameters.
      • IN THIS APPROPRIATE TYPE -7 CONTACT SURFACE ARE USED (TYPE7, variable stiffness, node to surface contact)
      • IN THIS MODEL THE TOTAL CAR AS CONSIDER MASTER AND SLAVE
      • THE REQUIRED PARAMETER FOR TYPE -7 CONTACT ARE GIVEN BELOW.
  • Make sure of no penetration and intersections.
        • IN TOTAL MODEL ALL THE SLAVE AND MASTER ARE ALIGN PROPERLY AND NO COLLISION FOUND
  • Create rigid wall with friction 0.1 as per referance model.
        • AS SIDE CRASH TEST WE GENERATE RIGID POLE
        • Pole-impact tests: A difficult test which places a large amount of force on a small proportion on the side of the vehicle.
        • IN ORDER TO GET BETTER VISUAL THE R WALL CREATED 150MM APART FROM THE MODEL
  • Compare the model weight with the referance model and use added masses to reach target weight 700kg while getting CG about the required range.
        • INORDER TO ACHIVE THE APPROPRIATE MASS THE MASS ADDED TYPE 0 AND MASS IS ADDED
        • IN CG POINT IS LAYING FRONT SIDE OF PASSEGER AREA
  • Initial velocity as shown in picture.
        • AS STANDARD THE CAR HIT ON THE R WALL AT 55 TO 60KM/HR IN ORDER TO MM/MS TO diveded by 3.6
        • IN ACCOUNT OUR CASE WE TAKEN 56KM/HR TOCONVERT MM/MS WE GET 15.64 MM/MS
  • Use model checker to ensure good quality.
        • TO AVOID RUN TIME ERROR WE CHECK THE MODEL
  • OUTPUT RESULT AND EXPLANATION
        • Sectional force in the cross member-1
          • THEY ARE TWO CROSS SECTIONAL FORCE IS MEASURED IN THE CROSS MEMBER
          • THE MARKED AREA SECTIONAL FORCE ARE MEASURED
          • AT THE TIME OF IMPACT THE FORCE TRANSMITTED IN PARTICULAR SECTION IS DIRECTLY PROPORTIONAL TO APPLYING THE FORCE
          • THE MAX RESULTANT FORCE OF THE REGION IS 5.71E-16 KN AT THE TIME OF 80MS AFTER.
        • Sectional force in the cross member-2
          • THE MARKED AREA SECTIONAL FORCE ARE MEASURED
          • AT THE TIME OF IMPACT THE FORCE TRANSMITTED IN PARTICULAR SECTION IS DIRECTLY PROPORTIONAL TO APPLYING THE FORCE
          • THE MAX RESULTANT FORCE OF THE REGION IS 8.8E-16 KN AT THE TIME OF 80MS AFTER.
          • WHEN COMPARING THE TWO CROSS MEMBER FORCE THE MEMBER -1 TRANSMITTING THE LESS FORCE SO,THE MEMBER 1 IS MORE STIFNESS THAN 2
        • Intrusion at B pillar
          • THE INTRUSION FORCE ON B PILLAR OF RESULTANT VELCOITY IS INTIAL STAGE IS AFTER THE TIME IT DECRESE DUE TO THE FORCE TRANSMITTING VARIOUS PARTS THE MAX VELCOITY OF AT THE INTIAL STAGE IS 15.64 MM/MS AND THE 80 TH MS IS 0.56MM/MS
          • AT THE SAME TIME THE INTRUSION OF THE DISPLACEMENT IN THE NODE IT SLOWLY INCREASE ACCORDING TO THE TIME. AT THE TIME OF IMAPACT 0 MS THE DISPACEMENT IS ALSO 0 BUT THE END OF THE TIME 80MS THE TOTAL DISPACEMENT IS 306 MM
        • Intrusion at hinge pillar
          • THE INTRUSION FORCE ON DRIVER SIDE OF RESULTANT VELCOITY IS INTIAL STAGE IS AFTER THE TIME IT DECRESE DUE TO THE FORCE TRANSMITTING VARIOUS PARTS THE MAX VELCOITY OF AT THE INTIAL STAGE IS 17.56 MM/MS AND THE 80 TH MS IS 7.99MM/MS. SO, IT SHOWS THE MORE ENERGY IS PASS THROUGH ONLY DRIVER SIDE WHENN COMPARING THE ABOVE FIG.
          • AT THE SAME TIME THE INTRUSION OF THE DISPLACEMENT IN THE NODE IT SLOWLY INCREASE ACCORDING TO THE TIME. AT THE TIME OF IMAPACT 0 MS THE DISPACEMENT IS ALSO 0 BUT THE END OF THE TIME 80MS THE TOTAL DISPACEMENT IS 864 MM SO, IT SHOWS THE MORE ENERGY IS PASS THROUGH ONLY DRIVER SIDE WHENN COMPARING THE ABOVE FIG.
        • Intrusion at fuel region
          • THE INTRUSION FORCE ON GAS TANK SIDE OF RESULTANT VELCOITY IS INTIAL STAGE HIGH IS AFTER THE TIME IT DECRESE DUE TO THE FORCE TRANSMITTING VARIOUS PARTS THE MAX VELCOITY OF AT THE INTIAL STAGE IS 15.95 MM/MS AND THE 80 TH MS IS 0.7 MM/MS.SO, IT SHOWS THE MORE ENERGY IS PASS THROUGH ONLY DRIVER SIDE WHENN COMPARING THE ABOVE FIG.
          • AT THE SAME TIME THE INTRUSION OF THE DISPLACEMENT IN THE NODE IT SLOWLY INCREASE ACCORDING TO THE TIME. AT THE TIME OF IMAPACT 0 MS THE DISPACEMENT IS ALSO 0 BUT THE END OF THE TIME 80MS THE TOTAL DISPACEMENT IS 292 MM.SO, IT SHOWS THE MORE ENERGY IS PASS THROUGH ONLY DRIVER SIDE WHENN COMPARING THE ABOVE FIG.
    • Peak velocity of inner node of the door.
          • THE PEAK VELCOITY OF THE NODE 337773 IS MAX VALUE IS 16.35MM/MS AT THE TIME OF INTIAL IMPACT T=0 AFTER THE COLLISION WITH R WALL THE ENERGY DISPATADED AT END THE IME THE VELCOITY OF THE NODE IS 2.23MM/MS
  • OTHER IMAGE AND EXPLANATION:
          • THE B PILLAR CROSS SECTIONAL FORCE MEASURE THE TIME OF SPAM 0-10MS THE MAX FORCE OCCUR THE 0.012KN FORCE AFTER THAT ENERGY IS PASS THROUGH THE ATTACHED COMPONENTS
          • THE ENERGY BETWEEN THE INTERNAL ENERGY AND KINETIC ENERGY IS INVERSLLY PROPOSTIONAL BECAUSE OF THE DURING THE IMPACT THE ENERGY RESISTANCE DUE TO THE INTERNAL ENERGY OF THE SYSTEM THE MAX INTERNAL ENERGY IS 22947.9J
          • SAME THAT the kinetic energy of an object is the energy that it possesses due to its motion THE MAX AND MIN KE WITH RESPECT TIME IS 83911.23J TO 584441.12J OVER THE TIME THE ENERGY IS DISSIPATED.
          • IN THE IMAGE SHOW VARIOUS VALUE IS THE
          • DISPACEMENT OF BODY IS 1480.151MM
          • PLASTIC STRAIN IS 1.487
          • VON MISSES IS 0.425
          • SPECIFIC ENERGY IS 91589.84 J/KG
          • THE TOTAL ENERGY ERROR IS -2.4<15% IS TRUE SIMULATION
          • TIME 79.90MS ANS TIME CYCLE 79900
          • MASS ERROR IS 0.1757E-7
  • CONCULSION
          • IN THIS ASSIGNMENT WE LAERN VARIOUS SECTION CRATION AND FORCE ACTING ON DRIVER SIDE, GAS TANK SIDE AND B PILLAR SIDE
          • AND FIND THE MAX VELCOITY NEAR BY DOOR AND MEASURING THE SECTIONAL FORCE ALSO.
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