Block mesh drill challange

Objective: Main objective is to design roof of a car and also to analyses roof curvature with the help of Heat distortion and snow load condition. What is roof? The external sheet metal part of any car which sits above passenger compartment is called roof panel which is mounted on and supported by roof bows. It act as…

Please find project link: https://skill-lync.com/projects/car-roof-design-challange   Thank you.

The main objective is to design the Drip Area, Sillmount area, bumper mount region and A-pillar mount Region for the front fender of the car. Fender is basically a sheet metal part which covers front wheel and rear wheel of the car.It protects the car body from the stones,chips and any kind of debris thrown by the rotating…

The main objective of this project is to examine that given wheel arc area of the car fender will pass the European standards or not. As per European standard,clearance length L between tire and wheel arc area of the fender at 5 cross-sectional areas such as at SA-SA,SB-SB,SC-SC,SD-SD and SE-SE as shown in the below image…

Please find project link below: https://projects.skill-lync.com/projects/Section-Modulus-54825 Thank you

The main objective is to calculate section modulus and optimise the model. Firstly,moment of the inertia(M) is calculated before applying embosses and reinforcement in the particular region of the hood.Please refer snapshot attached. Here,minimum moment of inertia i.e. MOI(min) is taken i.e. 1.37046e+004 mm^4  Y is…

Please find the project link for Hood design assembly. https://projects.skill-lync.com/projects/Hood-Design-00399   Thank you

Please find the google drive link for Hood assembly https://drive.google.com/file/d/14o2apfrQXFqm-81R2o6CUTFMJSAqErNU/view?usp=sharing Inner panel is designed and embosses are added as per requirement.Also hinge and striker are assembled with hood component.Please find snapdhot attached. Neccessary reinforcements are added…

Please find the answer in the below link : https://projects.skill-lync.com/projects/Underbody-Coating-08302  

It is process used to provide coating on the car surfaces by undergoing pretreatment,removal of execess metal and by electrodepositing of anti-corrosion layers.Under body protective coatings is used to protect the vehicle chassis from external environment, to ensure the integrity and safety of cars.The usage of coating…

Please find my answer in the project link mentioned below: https://projects.skill-lync.com/projects/Benchmarking-58053

I have selected 3 cars for Benchmarking as per the customer requirement, Mr.Pughazhyendhii is a fond of big car,so I have choosen 3 sedan type cars currently which are available in the market and it will fit best for long journey with mileage,comfort,safety and within his budget.Here are the list of cars classified with…

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Main objective is to simulate the flow of incompressible fluid through backward facing step.Geometry is generated with blockMeshDict file situated inside the cavity folder.Number of cells used in x,y and z directions are 200,10 and 1 respectively.IcoFoam solver is used to create different velocity,pressure contours and…

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Main Script: clear all close all clc %Inputs % Length of the domain L = 3 ; %Number of grid points n=31 ; %Number of points in x axis x=linspace(0,L,n); % Grid spacing dx = x(2)-x(1) % Area,a a = 1+2.2*(x-1.5).^2 ; gamma=1.4 ; % Exact node at the throat throat = ((n-1)/2)+1 ; % courant number c = 0.5 ; % No. of time steps…

https://projects.skill-lync.com/projects/Simulation-of-a-1D-Super-sonic-nozzle-flow-simulation-using-Macormack-Method-86944

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Main Script: clc clear all close all % Coefficient matrix A=[5 1 2;-3 9 4;1 2 -7]; %n=length(A); %RHS B=[10;-14;33]; %diagonal matrix D=diag(diag(A)); %lower diagonal matrix L=tril(A)-D ; %Upper diaginal matrix U=triu(A)-D ; %Effect of changing the diagonal element E=0.1:0.1:1; for i=1:length(E) D=E(i)*D %Calculating iteration…

Courant-Friedrichs-Lewy(CFL) number plays an important role in detremining stability of the system. For transient state, when diffusion term is involved,CFL term is defined as CFL=alpha.(dt/dx^2) where alpha is Thermal Diffusivity when dx term is increased by a factor of 2,we need to decrease the value of dt by factor…

Steady state analysis is independent of time marching,temperature gradient doesnot changes with respect to time,whrereas in unsteady state involves time marching solution,temperature gradient changes with respect to time. Steady state provides solution at a faster rate as compare to transient state both implicit and explicit…

  clear all close all clc %Initial condition L=1; %Length [m] nx=10; %Nodes in x direction ny=nx; %Nodes in y direction %Discretising in x-direction x=linspace(0,L,nx); y=linspace(0,L,ny); dx=L/(nx-1); dy = L/(ny-1); %Tolerance criteria error = 9e9; tol = 1e-4 ; %Assuming tremperature t=5; dt=1e-2 ; alpha = 0.1; %Steady…

https://projects.skill-lync.com/projects/aa-61226

Program to compute and compare difference between initial and final velocity profile with varying time steps such as 1e-4, 1e-3, 1e-2, and 1e-1. clear all close all clc %Time steps to use = 1e-4, 1e-3, 1e-2, and 1e-1 %input for the linear convection problem L=1; %Make the comparison for n=20,40,80 and 160 n=80; c=0.1;…

Here the objective is to derive 4th order approximations of the second order derivative of the analytical function exp(x)*cos(x) and compare it with the 3 numerical approximations such as in forward difference scheme(FDS),backward difference scheme(BDS) and Central Difference(CDS) and with the help of plot to compare the…

Program that computes difference between initial and final velocity profile,where n=20,40,80 and 160 clear all close all clc %input for the linear convection problem L=1; %Make the comparison for n=20,40,80 and 160 n=[20 40 80 100]; c=0.1; dt= 1e-2; %Total time in sec T= 0.4 ; % Total number of time steps nt=T/dt ; %Calculations…

Please find project link: https://projects.skill-lync.com/projects/kk-35744   Project Title: write a program in Octave to evaluate the second order derivative of the analytical function exp(x)*cos(x) and compare it with the 3 numerical approximations

Project: Simulating motion of a simple pendulum by solving differential equation Project link: https://projects.skill-lync.com/projects/Simulating-motion-of-a-simple-pendulum-by-solving-differential-equation-16084  

  %PROGRAM TO SIMULATE MOTION OF SIMPLE PENDULUM clear all close all clc %Inputs l=1; %Length of the string in m g=9.81; %Gravity in m/s^2 m=1; %Mass in kg b=0.05; %For simplification r=g/l ; k=b/m ; %Initial conditions theta_0=[0,3]; %[Angular displacement,Angular-velocity] %Time t_span=linspace(0,20,500); %Pendulum…

%Computing the first, second and fourth order approximations for a given value of dx. clear all close all clc %analytical function =sin(x)/x^3 %analytical derivative % f'(x)=(x^3(cos(x))-sin(x)*3*x^2)/x^6 ; x= pi/3 ; analytical_derivative=(x^3*(cos(x))-sin(x)*3*x^2)/x^6 ; % numerical derivative % forward differencing=…

% Program that compares the first, second and fourth order approximations clear all close all clc %analytical function =sin(x)/x^3 %analytical derivative % f'(x)=(x^3(cos(x))-sin(x)*3*x^2)/x^6 ; x= pi/3 ; analytical_derivative=(x^3*(cos(x))-sin(x)*3*x^2)/x^6 ; % numerical derivative % forward differencing= (f(x+dx)-f(x))/dx…