Week 5 - Genetic Algorithm

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Question 1:   False : Battery alone is not a better choice, its always smart to include UC's for the transient power demand support. considering the rapid accleration the chance of motor operating at higher power rating is possible, the battery alone can't support this transient power requirement, UC's got a nature of…

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  Given: motor max power = 40KW ;  motor max voltage : 110 from data sheet: Max Charge Voltage = 4.2 V ;  Max Pulse Discharge Current = 2.6 Amps Power delivered by one cell = 4.2 * 2.6 = 11 Watts no.of cell required in series to meet the requried voltage = 110/4.2 = 27 cells current = power/Voltage = 40*1000/110…

- Main Code : close all clear all clc input_file = fopen("THERMO.dat", "r"); R = 8.3145; % Universal Gas constant J/Mol*Km for o = 1:218 Y{o} = fgetl(input_file); end %--------------------------------Passing the element Name ---------------% prompt = "Enter species name O2, N2 or CO ? ";%Enter the element in the list :…

close all clear all clc %-----------------------------------user inputs---------------------% Temp1 = "What is Temperature 1 in celsius? "; T1 = input(Temp1); %turbine inlet temperature Pressure1 = "What is pressure 1 in Bar? "; P1 = input(Pressure1); %turbine inlet temperature Pressure2 = "What is pressure 2 in Bar? ";…

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% Function Code%%%%%%%%%%%%%%%%%%%%%%% function [f]= stalagmite_function(input) %calcuating f1 x & Y f1_x= (sin((5.1*pi).*input(1)+0.5)).^6; f1_y= (sin((5.1*pi).*input(2)+0.5)).^6; %calculating f2 x & Y f2_x= exp((((input(1)-0.0667).^2)/0.64).*(-4*log(2))); f2_y= exp((((input(2)-0.0667).^2)/0.64).*(-4*log(2)));…

%%%%%%%%%%%%%%%%%%%%%%%%%%%%% Function code %%%%%%%%%%%%%%%%%%%%%%% function [dtheta_dt] = ode_func(t,theta,b,g,l,m); theta1=theta(1); theta2=theta(2); dtheta1_dt = theta2; dtheta2_dt = -(b/m)*theta2 - (g/l)*sin(theta1); dtheta_dt = [dtheta1_dt;dtheta2_dt]; end %%%%%%%%%%%%%%%%%%%%%%%%%%% Main Code %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%…

clear all close all clc % lenght of two link link_1 = 2; link_2 = 1.5; ct = 1; % angle of link_1 and link_2 angle_1 = linspace(0,90,10); angle_2 = linspace(0,90,10); for i = 1:length(angle_1); theta_1 = angle_1(i); for j = 1: length(angle_2); theta_2 = angle_2(j); %(x0,y0) cordinate points x0 = 0; y0 = 0; %(x1,y1) cordinate…

Question 1: finding velocity : At point U initial velocity, u = 0  h = 90 V^2 - U^2 = 2gh Velocity , V = 42.02 ms-1 ----> 1 At point V : KE = 3(PE) 1/2 mv^2 = 3(mgh) subs V = 42.02 ms-1; g = 9.81 ; m =1.2kg h = 30m ----> Answer (height at V from ground)   Question 2 :   Question 3: Total reistance…