Challenge

Week 5 - Compact Notation Derivation for a simple Mechanism

FINDING THE REACTION RATE ODEs AND PRODUCTION RATE

Notation

j

Species

1

CO

2

O2

3

CO2

4

O

5

H2O

6

OH

7

H

Reactant mole concentration matrix(vji’)(matrix A)

The first column is for species 1 , the second column for second species and so on, row are no. as perreaction no.1,2,3,4. Here the vji notation does not mean that j is row and i is column , it is actually just a way of saying that the 'j' species in the reaction no. 'i' and the actual order of matrix is i x j.

1 1 0 0 0 0 0

0 0 0 1 1 0 0

1 0 0 0 0 1 0

0 1 0 0 0 0 1

Product mole concentration matrix(vji’’)

0 0 1 1 0 0 0

0 0 0 0 0 1 1

0 0 1 0 0 0 1

0 0 0 1 0 1 0

Both matrix are of size I x j, where i=no. of reactions and j=no. of species

Here the matrix size is 4 x 8

Vji’-vji’’=vji

Transpose of the subtraction of matrix A and B gives the matrix with notation vji.(to get order j x i now).

Vji=Net mole concentration matrix

1 0 1 0

1 0 0 1

-1 0 -1 0

-1 1 0 -1

0 1 0 0

0 -1 1 -1

0 -1 -1 1

This is an 8 x4 matrix with notation as vji.

q=kf∏[x](for vji')-kr∏[x](for vji'')

[x] =concentration of species

[x] for vji'=concentration of species at the reactant side(no. of moles)

[x] for vji''=concentration of species at the product side(no. of moles)

kf=forward reaction constant

kr=reverse reaction constant

eg-q1=kf1(product of concentration of reactants in reaction1(i.e first row)^vji')-kr1(product of concentration of products in reaction1(i.e. first row in product side)^vji'')

q1=kf1[CO]^1[O2]^1-kr1[CO2]^1[O]^1

q2=kf2[O][h2o]-kr2[OH][H]

q3=kf3[CO][OH]-kr3[CO2][H]

q4=kf4[O2][H]-kr4[OH][O]

q matrix is 4 x1 matrix,i.e

q1

q2

q3

q4

ωj=production rate of species

ω matrix is, an 8 x1 matrix

ω1 = d/dt[CO]

ω2 = d/dt[O2]

ω3 = d/dt[CO2]

ω4 = d/dt[O]

ω5 = d/dt[h2O]

ω6 = d/dt[OH]

ω7 = d/dt[H]

ωj=∑qi x vji, i.e summation of product of reaction rate and mole concentration matrix

CO is species 1, in vji matrix, v11 means v for species1 in reaction 1

ω for CO is q1(v11)+q2(v12)+q3(v13)+q4(v14) i.e.

ω for CO is (kf1[CO][O2]-kr1[CO2][O])(1) +(kf3[CO][OH]-kr3[CO2][H])(1)

similarly for all species, i.e the production matrix is ,

ω=8 x 1 matrix

Vji=8 x 4 matrix

q= 4 x1 matrix

i.e. ω=vji x q is the final matrix.

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