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Symmetry vs Wedge vs HP equation

  problem specification:  let us assume a cylindrical pipe of 0.01m diameter and length 2m  Fluid flowing with a velocity of 15m/sec with a kinematic viscosity of  1e-4 sqm/sec . d = 0.01m. nu = 1e-4 sqm/sec. v = 15m/sec. l = 2m. rho = 1000 kg/cubicm. mu = 10 Ns/sqm. outlet is open…

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Read more Projects by PASUVULA SAI KIRAN (5)

Symmetry vs Wedge vs HP equation

Objective:

  problem specification:  let us assume a cylindrical pipe of 0.01m diameter and length 2m  Fluid flowing with a velocity of 15m/sec with a kinematic viscosity of  1e-4 sqm/sec . d = 0.01m. nu = 1e-4 sqm/sec. v = 15m/sec. l = 2m. rho = 1000 kg/cubicm. mu = 10 Ns/sqm. outlet is open…

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17 Dec 2020 03:49 AM IST

  • CFD
  • MATLAB
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Simulation of Flow through a pipe in OpenFoam

Objective:

Your Answers problem specification:  let us assume a cylindrical pipe of 0.01m diameter and length 2m  Fluid flowing with a velocity of 15m/sec with a kinematic viscosity of  1e-4 sqm/sec . d = 0.01m. nu = 1e-4 sqm/sec. v = 15m/sec. l = 2m. rho = 1000 kg/cubicm. mu = 10 Ns/sqm. outlet…

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15 Sep 2020 01:33 AM IST

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Fluid flow through a y duct using ansys

Objective:

  Problem statement:     Design in SpaceClaim:       Meshing:     Outlet:     Inlet:     Ansys Fluent:      Temp variation               outlet velocity  5.1187422 m/s  outlet temp   305.65005 …

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26 Feb 2020 12:46 AM IST

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    Simulation of a 1D Super-sonic nozzle flow simulation using Maccormack Method

    Objective:

    OBJECTIVE: Simulation of a 1D super-sonic nozzle flow simulation using Macormack method we implement both the conservative and non-conservative forms of the governing equations and write code for solving 1D supersonic nozzle flow equation using the Macormack method. we also perform the grid-dependent test.   …

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    30 Sep 2019 01:50 AM IST

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      Taylor table method and Matlab code

      Objective:

      1.      Taylors table for five nodes central differencing for the fourth-order approximation of the second derivative.   stencil f(i) xf’(i) x^2*f’’(i) x^3*f’’’(i) x^4*f’’’’(i) af(i-2) a -2a 4a/2 -8a/6 16a/24 bf(i-1) b -b b/2 -b/6 b/24 cf(i)…

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      13 Jul 2019 09:56 PM IST

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        Showing 1 of 5 projects