Fluid flow through a y duct using ansys
Problem statement: Design in SpaceClaim: Meshing: Outlet: Inlet: Ansys Fluent: Temp variation outlet velocity 5.1187422 m/s outlet temp 305.65005 …
PASUVULA SAI KIRAN
updated on 26 Feb 2020
Project Details
Leave a comment
Thanks for choosing to leave a comment. Please keep in mind that all the comments are moderated as per our comment policy, and your email will not be published for privacy reasons. Please leave a personal & meaningful conversation.
Other comments...
Be the first to add a comment
Read more Projects by PASUVULA SAI KIRAN (5)
Symmetry vs Wedge vs HP equation
problem specification: let us assume a cylindrical pipe of 0.01m diameter and length 2m Fluid flowing with a velocity of 15m/sec with a kinematic viscosity of 1e-4 sqm/sec . d = 0.01m. nu = 1e-4 sqm/sec. v = 15m/sec. l = 2m. rho = 1000 kg/cubicm. mu = 10 Ns/sqm. outlet is open…
17 Dec 2020 03:49 AM IST
Simulation of Flow through a pipe in OpenFoam
Your Answers problem specification: let us assume a cylindrical pipe of 0.01m diameter and length 2m Fluid flowing with a velocity of 15m/sec with a kinematic viscosity of 1e-4 sqm/sec . d = 0.01m. nu = 1e-4 sqm/sec. v = 15m/sec. l = 2m. rho = 1000 kg/cubicm. mu = 10 Ns/sqm. outlet…
15 Sep 2020 01:33 AM IST
Fluid flow through a y duct using ansys
Problem statement: Design in SpaceClaim: Meshing: Outlet: Inlet: Ansys Fluent: Temp variation outlet velocity 5.1187422 m/s outlet temp 305.65005 …
26 Feb 2020 12:46 AM IST
Simulation of a 1D Super-sonic nozzle flow simulation using Maccormack Method
OBJECTIVE: Simulation of a 1D super-sonic nozzle flow simulation using Macormack method we implement both the conservative and non-conservative forms of the governing equations and write code for solving 1D supersonic nozzle flow equation using the Macormack method. we also perform the grid-dependent test. …
30 Sep 2019 01:50 AM IST
Taylor table method and Matlab code
1. Taylors table for five nodes central differencing for the fourth-order approximation of the second derivative. stencil f(i) xf’(i) x^2*f’’(i) x^3*f’’’(i) x^4*f’’’’(i) af(i-2) a -2a 4a/2 -8a/6 16a/24 bf(i-1) b -b b/2 -b/6 b/24 cf(i)…
13 Jul 2019 09:56 PM IST