Challenge

Section Modulus calculation and optimization

1) For Front Impact

The Moment of Inertia(I) of this Hood part is 6*10^7 kgxmm2

and the distance between the neutral axis and the extreme end of the object (Y) is = 934.98/2=467.49mm

So, The Section Modulus of this part is= 6*10^7/467.49=128.345*10^3 kg-mm

2) For Top Impact

The Moment of Inertia(I) of this Hood part is 6*10^7 kgxmm2

and the distance between the neutral axis and the extreme end of the object (Y) is = 80.6/2=40.3mm

So, The Section Modulus of this part is= 6*10^7/40.3=1488.833*10^3 kg-mm

Ship work like this
in your own course.