Challenge

Roof challenge

For the Given Roof styling, Develop the essential flanges and reinforcements, Provide appropriate dimensions and check for Draft analysis, and submit your Section Inertia report on the 0-Y section.

Start with the creation of a roof ditch area the tool opening angle is only 3 degrees.

Do a curvature study on the roof and perform calculations to determine the position of the Bow-roof

Design Requirements for the ROOF and its components
Functional Requirements
Types of Roofs and their
Functionality
Rollover test Regulation BO and Requirement
Identification Methods to Increase theStrength of the ROOF (ROOF BEAD)
Material Identification Techniques
Joining Techniques like Mastic,
Welding
Accessory part Purpose and requirements (Rool RACK and Roof MOLDING
Roll over test requirement and Regulation
GAP and FLUSHNESS

Front roof rail

TYPICAL SECTIONS - ROOF RAIL RR LWR

Approach:

Removal of surface and maintain surface similar to roof side rail

Increase strength

Smooth area connection with PLR RR INR

Effective material usage

TYPICAL SECTIONS - REINFORCEMENT ROOF CTR

Approach:

Addition of mastic bead area in reinforced roof center

Increase strength.

Since mastic bead added -> possibility to reduce bow roof 1

Thickness reduced from base (2.3 >> 1.5) mass reduction

Usage of high tensile material > increase in strength

COMMENTS USED

Extract geometry

Wave link

Offset surface

offset curve in face

trim sheet

project curve

studio surface'

emboss

bridge curve

face blend

edge blend

sew

thicken

mirror geometry

Section inertia

Bow–roof prediction Formula

W = [1.73 x 10^(-3) x L] + [1.85 x 10^(-8) x (R^2)/t] + [ 1.10x10^(-3) x l] - 2.68

Judgement Condition : OK< 2.7> 3.1

Where

L = Roof Length in X-Direction[mm](Roof dimension in 0-Y)

R = Roof curvature

R = 2(Rx*Ry)/(Rx+Ry)

Rx = X curvature

Ry = Y curvature

t = Roof plate thickness [mm]

l = Bow Roof Span [mm]

Snow load Prediction formula

Qr = [Iy x t2] / [α x s x [(Rx + Ry)/2]2 x 10-8]

Note: The Qr value given over here is correct. There was a typo error in the formula given in the video.

Where

α = My x Lx2 x 10-12 , My = Y(Ly-Y)

Judgement condition = Qr ≥ 3.1

250 ≤ s ≤ 380

t = Roof plate thickness [mm]

Ly = Distance between the front and rear roof Rails on the Vehicle along with 0Y[mm]

Length of Roof panel with the center point between Roof rail Front /Rear as the front and rear reference point.

Lx = Distance between the Left and Right end of the roof on the Roof BOW [mm]

Width of the roof panel exposed on the surface.

Y = Distance front Front Roof Rail to Roof BOW[mm]

s = Distance for which Roof BOW bears divided load [mm]

s = L1/2 + L2/2

Iy = Geometrical moment of inertia of Roof BOW (Y cross-section )[mm4]

Rx = Lateral direction curvature radius of roof panel Y cross-section on Roof BOW [mm]

Roof panel curvature Radius of the Length Lx in Front view

Ry = Longitudinal Direction curvature radius of the Roof panel X cross-section on Roof BOW [mm]

Roof panel X curvature radius of length s in Side view

The heat disortion has been passed and the snow load is not

In the snow load calculation bow 1 has been failed.the curvature can be increased and modified to pass

Bow roof 1

Front roof rail

centre rail reinforcement

rear roof rail

bow roof 2

Thus the rood design is done with the components and optimized for heat disortion and snow load.

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