Challenge

Project 2

Ans 1-

Aim- Design a Warehouse Building located in Chennai using STAAD Pro Connect Edition. The specification must be as follows:

  • Width 30m
  • Length 50m
  • Eave Height 9m
  • Bay Spacing 6m
  • Soil Type Medium
  • Safe Bearing capacity 200KN/m^2
  • Roof slop 1in 12

calculation of slop

`x/(d/2)=1/12`

=x/(30/2)=1/12

x=15/12

x=1.25m

Creat the model in the staad pro software

step2. Define the section property then select the property and select the section and assign the property

step 3

go to material and assign the steel material in the hole structure

Step 4. go to support and creat the support and assign the support in the base of structure

Step 5 go to spection and select the beam and assign the structure

Step6 go for the applying the load frist calculate the load DL , LL, WL, WL etc

DEAD LOAD ON RAFTER

Self weight

FOS=1.5

-UDL on rafter (main frame)

Weight of roof sheeting = 5Kg/m^2

weight of sag rod and bresses = 5Kg/m^2

Collateral loads = 10Kg/m^2

Total loads=20Kg/m^2

UDL on rafter

Spacing = 6m

UDL=0.2X6= 1.2KN/m

UDL on Rafter from purlin (IS 811)

Sag Z=270x75x20x2.55 = 8.77 Kg/m

(9x6x8.77)/15=31.572

= 0.32 Kg/m

Total UDL on main frame

1.2+0.32=1.52 KN/m

UDL on Globle frame

=1.52/2=0.76 KN/m

Weight of side wall sheeting = 5 Kg/m^2

Weight of sag rods & braces =5 Kg/m^2

load from sag rods & branch = 10Kg/m^2

=0.1 KN/m^2

0.1*6=0.6 KN/m^2

weight of grit (270*75*20*2.55) = 8.77 Kg/m

(6*6*8.77)/6=52.66

=0.53 KN/m

total load = 0.6+0.53=1.13 KN/m

load of column (Gable frame)

Total load =1.13/2=0.565 KN/m

Load on wind column

load from sheet & sag rods = 0.1*6=0.6KN/m

weight of grits (230*75*20*2)=6.32 Kg/m

=(6*6*6.32)/6=37.92 Kg/m

=0.38 KN/m

Total load = 0.6+0.38=0.98 KN/m

1.16 for the main frame

0.58 for the gable frame

LIVE LOAD CALCULATION

live load on roof =0.75 KN/m^2 (IS 875-11)

UDL on Rafter

main frame rafter= 0.75*6=4.5 KN/m

Gable frame Rafter= 4.5*.5=2.25 KN/m

Eave gutter (250*250*1mm)

main frame (0.25*0.25*10*6)=3.75

Gable frame =0.5*3.75=1.875 KN/m

WIND SPEED DESIGN-

Vb=50m/s

  • K1 = 1
  • K2 = 1
  • K3 = 1
  • K4 = 1.15

Vz=50*1*1*1*1.15

=57.5 m/s

wind pressure

Pz=0.6*(57.5)^2

1.984 KN/m^2

Wind load on members F = (Cpe-Cpi)*A*Pd
External pressure coefficient Cpe =
Internal pressure coefficient Cpi = -5
Length of building L = 50 m
width of building W = 30 m
height of building h = 9 m
ratio L/w = 1.67
h/W = 0.3
Roof angle 1 in 12 = 4.76 degree
5 degree
Design wind pressure Pd = 1.983 KN/m^2
governing spacing for rafter = 6 m
for gable column = 6 m
0 90
EF GH EG FH
-0.9 -0.4 -0.8 -0.4
Degree A B C D
0 0.7 -0.25 -0.6 -0.6
90 -0.5 -0.5 0.7 -0.1
Internal pressure coefficient Cpi = 0.5
Cpi = -0.5
Cpe Cpi(+) Cpi(-) (Cpe-Cpi) Cpe-Cpi Pd for "+" Pdfor"-"
-0.9 0.5 -0.5 -1.4 -0.4 -14.52 -4.15
-0.4 0.5 -0.5 -0.9 0.1 -9.34 1.04
-0.8 0.5 -0.5 -1.3 -0.3 -13.49 -3.11
-0.4 0.5 -0.5 -0.9 0.1 -9.34 1.04
Internal pressure coefficient Cpi = 0.5
Cpi = -0.5
Cpe Cpi + Cpi - Cpe-Cpi + Cpe-Cpi "-" Pd fpr "+" Pd for"-"
0.7 0.5 -0.5 0.2 1.2 2.07 12.45
-0.25 0.5 -0.5 -0.75 0.25 -7.78 2.59
-0.6 0.5 -0.5 -1.1 -0.1 -9.78 -0.89
-0.6 0.5 -0.5 -1.1 -0.1 -9.78 -0.89
-0.5 0.5 -0.5 -1 0 -10.37 0
-0.5 0.5 -0.5 -1 0 -10.37 0
0.7 0.5 -0.5 0.2 1.2 1.78 10.67
-0.1 0.5 -0.5 -0.6 0.4 -5.34 3.56

then design the structure select the is code IS 800:2007

4 Design using MS excle

  • STEEL COLUMN
Title Design of column
Height of column = 9 m
Reaction load = 123 KN
Moment = 116 KNm
Yield strength = 250 N/mm^2
Design compressive stress = 80 N/mm^2
step 1 Recuride cross sectional area
Cl 7.3.2 Area required = 1537.5 mm^2
step2 Property of selected section
ISHB 300 mm^2
A 7485 mm
h1 249.8 mm
B 125 mm
t 7.6 mm
T 10.6 mm
rx 12.95 cm^4
Lyy 2193.6 cm^4
Zx 836.3 cm^3
Flange criterion b/tf = 11.79
Web critection h/tw = 32.87
E = 1.77
b/tf > 10.5
h1/tw < 84
The section is classified as semi COMPACT
step 3 Section strength
Axial stres N/Ac = 16.43 N/mm^2
Banding stress Mz/Ze = 138.71 N/mm^2
Horizontal stres V = 13 Kn
Vd = ((fy/(3)^1/3)*h*tw)/1.1
Vd = 299.17 KN
V/Vd = 0.04
< 0.6
So reduction in moment capacity need not be done
Cl 9.3.1.3 Total longitudinal compressive stress = 155.14 N/mm^2
fx < 227.27 N/mm^2
P = 123 Kn
Pd = Ag.fy/ym
= 1701.14 KN
= 116 KNm
= 190.1 KNm
= 0.68
< 1
step4 check for buckling failure
Cl 9.3.2 Mdz = Bq.Zp.Fbd
Bq = Ze/Zp
Fbd = XLT.Fy/ym
a = 0.21
KL = 7.2 m
KL/ry = 133.09 mm
T14 fcr = 197.1 N/mm^2
lemda = 1.13
> 0.4
Cl 8.2.2 Mdz = 190.1 KNm
T10 h/bf = 1.2
tf= 10.6 < 100 mm
ly/ry = 133.09
T9c fcdy = 88.3 N/mm^2
Pdy = 660.962 KN
lz/rz = 55.6
T9b fcdz = 195 N/mm^2
Pdz = 1459.58 KN
nz = 0.08
ny = 0.19
lemda z = 0.25
Kz = 1
< 1.07
unity check
< 0.67
< 0.57
1
  • Rafter
Title Design of rafter
Span of rafter = 6 m
Dead load = 2.784 KN/m
Imposed load = 7.875 KN/m
Length of bearing = 100 mm
yield strength = 250 N/mm^2
step 1 Design of load calculation
factored load = 15.9885 KN/m
factored banding moment = 71.94825 KN/m
step2 section modulas required
Z reqd = 316572.3 mm^3
= 316.5723 cm^3
step3 section classification
property of selected section
ISMB 250
A 475.5 MM^2
D 250 mm
B 125 mm
t 6.9 mm
T 12.5 mm
lzz 5131.6 cm^4
lyy 344.5 cm^4
Zp 459.76 cm^3
falng criterion B/2T = 5
web criterion (D-2T)/t = 32.6087
E = 1
B/2T < 9.4
(D-2T)/t < 83.9
the section is classified as plastic
step4 moment of the resistance of the cross section
moment Md = (Zpxfy)/ym
mMd = 104.491 KNm
>71.95
step5 shear resestance of the cross section
Shear capacity Vc = 0.6fyAv/ym
Av = 1725 mm^2
Vc = 235.23 KN
V = 47.97 KN
V/Vc = 0.2
< 0.6
step6 check for web buckling
slenderness ratio of web = 2.5d/t
d = 225
= 70.33
Design compresive strength = 203 N/mm^2
= 315158
= 315.16 KN
> 126
Hence web is safe againest shear buckling
step7 check for web crippling support
Root radious of ISMB 250 R = 13 mm
tf+R = 25.5 mm
Dispersion length n2 = 63.75 mm
Pcrip = 245625 N
= 245.625 KN
> 126
Hence section adequate for web crippling
step8 Check for serviceability - Deflection
Design load = 10.659 KN/m
deflection = 17.53 mm
Allowable deflection = 30 mm
Hence serviceability is satisfied

Base plate

Title Design of Base plate
step1 strength of concrete = 40 N/mm^2
yield strength of steel = 250 N/mm^3
Material factor = 1.1 KN
factored load = 600 KN
step2 steel column section
Thickness of flange T = 12.7 mm
step3 Area required
bearing strength of concrete = 0.4fcu
= 16 N/mm^2
Area required = 37500 mm^2
Let size of plate B plate = 450 mm
D plate = 300 mm
Area of plate = 135000 mm^2
Let projection of each side a=b = 25 mm
w = 4.44 N/mm^2
Cl 7.4.3.1 Thickness of slab base ts = 4.6 mm
< 12.7 mm
so use base plate of size 450mm x 350mm x 16mm

Pedestal

title Design of pedestal
Grade of concrete = 40 N/mm^2
load = 123 KN
Moment = 116 KNm
Horizontal shear = 13 N/mm^2
yield strength = 250 mm
Length of base plate = 450 mm
width of bae plate = 350 mm
c/c distance of (Ld) of bolt grup in z = 300 mm
c/c distance of (Ld) of bolt grup in x = 180 mm
Bearing strength of concrete 'fc' = 16 N/mm^2
depth of column = 300 mm
width of column = 250 mm
step1 Anchor Bolt Details
Dia of Anchoe bolt = 24 mm
No (n) of anchor bolt of each side = 4
Total number of anchor bolt n = 8
Gross area of bolt 'Asb' = 452.16 mm^2
Net area of bolt 'Anb' = 352 mm^2
Ultimate tensile strength of the nolt 'fub' = 400 N/mm^2
Fyb (Anchor Bolt) = 240 N/mm^2
step 2 Base plate Details
Ultimate tensile strength of a plate, 'fu' = 490 N/mm^2
Thickness of plate = 16 mm
yield stress of plate = 330 N/mm
step3 Anchor bolt design
Area of the plate = 157500 mm^2
Stress max pressure,01 = F/A+6*Mz/BL^2
= -9.04 N/mm^2
< 16
ok
Min pressure 02 = F/A+6*Mz/BL^2
= -9.04
< 16
ok
C=L*01/(01+02) = 242.89 mm
a=L/2-C/3 = 144.04 mm
e=(L-Ld)/2 = 75 mm
y=(L-C/3-e) = 294.04 mm
Tension in anchor bolts along the plate
FT = (Mz-F*a)/y
= 364.38
Tension per bolt = 91.1 KN
Shear per bolt, V = 1.63 KN
step4 shear check
Factor shear force Vsb = 1.63 KN
Vd,b = 81290.9 N
= 81.29 KN
Factored Vd,sb = 65.03 KN
step5 Tensile check
Factored tensile force in both Tb = 91.1 KN
Tensile strength of bolt Td,b = Tn,b/ymb
Tn,b = 0.9*fub*An
= 126720 N
= 126.72 KN
Tn,b = fyb*Asb*(ymb/ymo
= 123316 N
= 123.32 KN
Lesser of two = 123.32 KN
so, Td,b = 98.65 KN
step6 Combined unity check
(Vsb/Vdb)^2+(Tb/Tdb)^2 Vsb/Vdb = 0.025
Tb/Tdb = 0.92
Unity check = 0.85
< = 1
ok
step7 Anchor bolt length
Bond strength in tension Tbd = 1.4 N/mm^2
Anchor length required = Tb(3.14*d*Tbd)
= 863.44 mm
let anchor bolt length = 900 mm

Ans 2 check in the attech file

Your portfolio, next

Ship work like this
in your own course.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.