Project 2

1.) Given Data:

1. Input voltage: 45 – 60 v
2. Output voltage: 3 V
3. Output current: 100A
4. Efficiency > 85%

Assumptions:

1. Switching frequency= 20000H
2. Duty ratio= 0.5

Calculation:

For this design we are using the Forward converter formulas:

1) Duty cycle:

VoutVi=D⋅(N2N1)VoutVi=D⋅(N2N1)

Let's assume that we will design for a 50% Duty ratio:

N2N1=0.1N2N1=0.1

We chose the following:

N1= 500

N2=50

Since we chose D=0.5 then using the equation we found that,

D(1+N3N1)<1D(1+N3N1)<1

thusN3N1<1thusN3N1<1

Thus we will choose,

N3= 150 turns

Now, we will choose an inductor for 40% current ripple:

R=V2outP=0.03R=Vout2P=0.03

IL=VoR=100AIL=VoR=100A

L=VoutFs⋅ΔIl⋅(1−D)L=VoutFs⋅ΔIl⋅(1-D)

L=1.5e−6

Now we are calculating the Capacitor:

C=1−D8L⋅FS2(ΔVOVo)C=1-D8L⋅FS2(ΔVOVo)

C=20.83e−6

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2.)