Challenge

Project 1 - Creation of user defined data type to implement the user interfaces for working with ‘Set’ (Mathematical Set theory) using Linked List

#include
#include
#include
// Link list node
struct Node
{
    int data;
    struct Node* next;
};
//function declaration
void push(struct Node** head_ref, int new_data);
int isPresent(struct Node* head, int data);
// Function to get union of two linked lists head1 and head2
struct Node* getUnion(struct Node* head1, struct Node* head2)
{
    struct Node* result = NULL;
    struct Node *t1 = head1, *t2 = head2;
    // Insert all elements of list1 to the result list
    while (t1 != NULL)
    {
        push(&result, t1->data);
        t1 = t1->next;
     }
    // Insert those elements of list2 which are not present in result list
    while (t2 != NULL)
    {
        if (!isPresent(result, t2->data))
        {
            push(&result, t2->data);
        }
        t2 = t2->next;
    }
    return result;
}
// Function to get intersection of two linked lists head1 and head2
struct Node* getIntersection(struct Node* head1, struct Node* head2)
{
    struct Node* result = NULL;
    struct Node* t1 = head1;
    // Traverse list1 and search each element of it in list2. If the element is present in list 2, then insert the element to result
    while (t1 != NULL)
    {
        if (isPresent(head2, t1->data))
        {
            push(&result, t1->data);
        }
        t1 = t1->next;
    }
    return result;
}
// A utility function to insert a node at the beginning of a linked list
void push(struct Node** head_ref, int new_data)
{
    // allocate node
    struct Node* new_node = (struct Node*)malloc(sizeof(struct Node));
    // put in the data
    new_node->data = new_data;
    // link the old list off the new node
    new_node->next = (*head_ref);
    // move the head to point to the new node
    (*head_ref) = new_node;
}
// function to print a linked list
void printList(struct Node* node)
{
    while (node != NULL)
    {
        printf("%d ", node->data);
        node = node->next;
    }
}
// function that returns true if data is present in linked list else return false
int isPresent(struct Node* head, int data)
{
    struct Node* t = head;
    while (t != NULL)
    {
        if (t->data == data)
        {
            return 1;
        }
        t = t->next;
    }
    return 0;
}
// Driver program to test above function
int main()
{
    int n,m,temp;
    printf("enter the value of number of value in link list(both):");
    fflush(stdout);
    scanf("%d %d", &n, &m);
    // Starth structure pointer with the empty list
    struct Node* head1 = NULL;
    struct Node* head2 = NULL;
    struct Node* intersecn = NULL;
    struct Node* unin = NULL;
    //for loop for link list1
    for(int i=0;i    {
        printf("Enter the value in link list1 %d:",i);
        fflush(stdout);
        scanf("%d", &temp);
        push(&head1, temp);
    }
   //for loop for link list2
   for(int i=0;i   {
       printf("Enter the value in link list2 %d:-",i);
        fflush(stdout);
        scanf("%d", &temp);
        push(&head2, temp);


   }
   //call the function of intersection
    intersecn = getIntersection(head1, head2);
    //call the function of union
    unin = getUnion(head1, head2);
    printf("\n First list is ");
    //function calling with structure pointer as argument
    printList(head1);
    printf("\n Second list is ");
    printList(head2);
    printf("\n Intersection list is ");
    printList(intersecn);
    printf("\n Union list is ");
    printList(unin);
    return 0;
}
 
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