Challenge 4
Aim : To prepare a longitudinal model of I-girder and analyse for all the loads in Staad Pro
Introduction:
Given data of girder are
- Grillage model of 4 I-girders with span length of 27.0m.
- Having supports at 0.700m from both ends.
- Having following geometrical properties:
End Section: Area = 1.218m2
Iy = 0.32541m4
Iz = 0.05129m4
Mid Section: Area = 0.87702m2
Iy = 0.27835m4
Iz = 0.02622m4
4. Having material properties: Concrete, M60 grade
Others data's are assumed
























SLS LOAD COMBINATION = DL+1.2*SIDL+1.1*LL*I
I=Impact factor
Impact factor CDA as per IRS bridge rules will be 0.15+8/(6+L) = 0.15+8/(6+25.6) = 0.403.
Now this CDA is for broad guage as per IRS we have to calculate it for metro.
Speed for metro is 90km/hr whereas for Broadguage it is 116 km/hr
Therefore impact factor will be 0.403x(90/116)=0.313
Impact factor x Live load factor = 1.313 x 1.1 = 1.45 = factor for live load in SLS combination
Moment = 1725.9+1.2*1635.6+1.45*1152 = 5359.02 kNm
This moment is used for design
Prestress design
No.of cables =4
No.of strands (n) = (7 strands in 3 cable + 8 strands in 1 cable)= 7*3+8=29
Prestressing force applied (P) = 0.765fpu x As x n x (1-loss) / 1000 kN
fpu = Nominal ultimate stress = 1860 MPa
Maximum jacking stress = 0.765 fpu = 0.765 x 1860 = 1422.9 MPa
As = Area of strand = 140mm2
Assume loss of 17.5%
Prestressing force (P) = 4766 kN
Stress @ bottom of girder = Compressive stress due to tendons - tensile stress due to external loading
= ( P/A + P.e/Z) - (M/Z)
Z = I/y = 1.24m3
A = Sectional Area of girder = 1.04 m2 (Average)
P = 4766 kN as calculated above
e = centre of gravity of girder section @ bottom of girder- centre of gravity of tendon @ bottom of girder = 0.454m
M = moment of SLS combination from longitudinal analysis for DL, SIDL & LL combination = 5359.02 kNm
Therefore, Stress @ bottom of girder = 1.97 n/mm2 (Since the resultant stress is positive it is compressive, as to avoid tension we are providing tendons)