Air standard cycle

For Re= 100 For Re= 100   For Re= 1000   I applied the formula,  Re= Diameter*Velicity/Kinematic viscosity. I tried to calculate velocities for Re= 10000, but its not giving me the answer.

close allclear allclc f1 = fopen(\'thermo.dat\',\'r\')fgetl(f1)A = fscanf (f1,\'%f\')

om initial data set (population), then it creates a sequential new data set (Generation).For the next data, it uses the current generation. For creating new data from the current generation, it follows below steps-1- Scores each data point (member) of the current data set by computing its fitness value. These values are…

In order to make a curve fitting better, a higher degree polynomial should be chosen. This approach is used in the Finite Element Method (FEM) as well. (This is the answer of the second question)   In linear curve fitting, the curve is not getting good results because if we see the original curve and define it…

In this particular program, I choose Ideal gas equation (assuming atmospheric pressure (p1) and temperature (T1) under the normal condition, the volume (v1) is calculated).  Assuming Compression ratio of 10, we can calculate v2 and be using v1 & v2, p2 can be calculated. T2 can found by the using Isentropic compression…

clear all close all clc theta1 = linspace (0, 90, 20); theta2 = linspace (0, 90, 20); l1 = 1.25; l2 = .75; ct=1; for i = 1:length(theta1) THETA1 = theta1(i) for j = 1:length(theta2) THETA2 = theta2(j) x0 = 0; y0 = 0; x1 = l1*cosd(THETA1); y1 = l1*sind(THETA1); x2 = x1+l2*cosd(THETA2); y2 = y1+l2*sind(THETA2); plot([x0,…

% Inputs % Drag coefficient c_d = 1.28 % Frontal Area m^2 A = .5 % Density kg/m^3 rho = 1.5 % Velocity m/sec v = [4, 5, 6, 7, 8] drag_Force = rho*A*v.^2*c_d*.5

% Inputs % Drag coefficient c_d = 1.28 % Frontal Area m^2 A = .5 % Density kg/m^3 rho = 1.5 % Velocity m/sec v = [4, 5, 6, 7, 8] drag_Force = rho*A*v.^2*c_d*.5

X = [1,2;3,4;5,6;7,8] Y = [1 2 3 4 5] Z = [1;2;3;4;5]  

X = [1,2;3,4;5,6;7,8] Y = [1 2 3 4 5] Z = [1;2;3;4;5]  

X = [1,2;3,4;5,6;7,8] Y = [1 2 3 4 5] Z = [1;2;3;4;5]  

X = [1,2;3,4;5,6;7,8]   Y = [1 2 3 4 5]   Z = [1;2;3;4;5]

X = [1,2;3,4;5,6;7,8]   Y = [1 2 3 4 5]   Z = [1;2;3;4;5]